All categories

3 years ago

The purpose of an interface is to:___________

Computers and Technology

1 answer:

Galina-37 [17]3 years ago

8 0

Answer:

Purpose of the interface

Provides communication − One of the uses of the interface is to provide communication. Through interface you can specify how you want the methods and fields of a particular type.Jul

You might be interested in

The people on this platform are unbelievably nice. its almost rare to see this type of kindness online these days. Just wanted t

baherus [9]

Answer:

thanks

Explanation:

5 0

3 years ago

Direct Mapped Cache. Memory is byte addressable. Fill in the missing fields based upon the properties of a direct-mapped cache.

xz_007 [3.2K]

The question given is incomplete and by finding it on internet i found the complete question as follows:

Direct Mapped Cache.

Memory is byte addressable

Fill in the missing fields based upon the properties of a direct-mapped cache. Click on "Select" to access the list of possible answers Main Memory Size Cache Size Block Size Number of Tag Bits 3 1) 16 KiB 128 KiB 256 B 20 2) 32 GiB 32 KiB 1 KiB 3) 64 MiB 512 KiB 1 KiB Select] 4 KiB 4) 16 GiB 10 Select ] Select ] 5) 10 64 MiB [ Select ] 6) Select] 512 KiB 7

For convenience, the table form of the question is attached in the image below.

Answers of blanks:

1. 3 bits

2. 20 bits

3. 64 MB

4. 16 MB

5. 64 KB

6. 64 MB

Explanation:

Following is the solution for question step-by-step:

Part 1:

No. of Tag bits = No. of bits to represent

Tag bits = Main memory - cache size bits -------- (A)

Given:

Main memory = 128 KB = $2^7 * 2^{10} = 2^{17}$

Cache Memory = 16 KB = $2^4 * 2^{10}= 2^{14}$

Putting values in A:

Tag bits = 17 - 14 = 3 bits

Part 2:

Tag bits = Main memory - cache size bits -------- (A)

Given:

Main memory = 32 GB = $2^5 * 2^{30} = 2^{35}$

Cache Memory = 16 KB = $2^5 * 2^{10}= 2^{15}$

Putting values in A:

Tag bits = 35 - 15 = 20 bits

Part 3:

Given:

Tag bits = 7

Cache Memory = 512 KB = $2^9 * 2^{10} = 2^{19}$

So from equation A

7 = Main Memory size - 19

Main Memory = 7 + 19

Main memory = 26

Main Memory = $2^6 * 2^{20} = 64 MB$

Part 4:

Given that:

Main Memory Size = $2^4 * 2^{30} = 2^{34}$

Tag bits = 10

Cache Memory Bits = 34 - 10 = 24

Cache Memory Size = $2^4 * 2^{20} = 16 MB$

Part 5:

Given that:

Main Memory Size = 64 MB = $2^6 * 2^{20}$

Tag bits = 10

Cache Memory Bits = 26 - 10 = 16

Cache Memory Size = $2^{16} = 2^6 * 2^{10} = 64 KB$

Part 6:

Cache Memory = 512 KB = $2^9 * 2^{10} = 2^{19}$

Tag Bits = 7

Main Memory Bits = 19 + 7 = 26

Main Memory size = $2^{26} = 2^6 * 2^20 = 64 MB$

i hope it will help you!

6 0

3 years ago

Consider the relation Courses(C, T, H, R, S, G), whose attributes can be thought of informally as course (C), teacher (T), hour

k0ka [10]

Answer and Explanation:

a) Key for the relation courses is HS.

b) FD's are already minimal basis, as no attributes can be removed from the left side, right side is having only single attributes and none of the FD can be removed as given in the question.

c) By using the 3NF synthesis algorithm, the final set of relations obtained will be CT, HRC, HTR, HSR, CSG (FD'S are already proved to be minimal basis in part (b)). All the relations are in BCNF.

3 0

3 years ago

How do you run a function in python?

Black_prince [1.1K]

You can call a Python function like so: function(parameters).

Example:

Define function add:
def add(x,y):
return x+y

Call function:
add(3,7) -> 10

3 0

3 years ago

Which internet technology allows businesses to make presentations and share visual aids such as charts and graphs ?

Akimi4 [234]

Web conferencing is an internet technology that allows people in remote locations collaborate in a virtual conference room by making presentations and sharing visual aids.

Let me know if you have any questions.

8 0

3 years ago

Read 2 more answers