Answer:
4(x-7)^2-(x-7)+3 (Assuming t is f)
Step-by-step explanation:
Let s(x)=x-7 and t(x)=4x^2-x+3 .
(t o s)(x)=t(s(x))=t(x-7)
Before I continue this means replace the orginal x in t with x-7.
This will then give you
4(x-7)^2-(x-7)+3
Answer:
40
Step-by-step explanation:
30/75 = .4
Answer:
-2. 46
- 9.54
Step-by-step explanation:
- 2x²+12x-7=0
- 2x²+12x+18= 25
- 2*(x²+6x+9)=25
- 2*(x+6)²= 5²
- x+6= 5√2/2 ⇒ x= 5√2/2 -6 ≈ -2. 46
- x+6= -5√2/2 ⇒ x= -5√2/2 -6 ≈ - 9.54
<span>The value of y when x=3 when the value of y varies directly with x^2, and y = 150 when x = 5 is 54. Since the value of y varies directly with x2, then: y = k * x^2, where k is constant. When y = 150 and x = 5, the value of constant is: 150 = k * 5^2. 150 = k * 25. k = 150/25. k = 6. Thus, when x = 3, the value of y will be: y = 6 * 3^2. y = 6 * 9. y = 54.</span>
Answer: 4
Step-by-step explanation: 1/4 = 25% Hope This Helps
