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MariettaO [177]
3 years ago
15

Can someone please help me answer this question ASAP

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
6 0

Answer:

i looked it up and got 2 difernt answers one said -11 the other said 0 so im sorry idk

Step-by-step explanation:

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70 feet per minute.

21 minutes

1890 feet


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2/15 or 0.13

Step-by-step explanation:

first you multiply 2/3 and 1/5 which gets you 2/15

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Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
PLSSSS I NEED HELPPPPP
Gelneren [198K]

Step-by-step explanation:

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