1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
il63 [147K]
3 years ago
9

Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and

determine the smallest, largest, average, and calculate the standard deviation. Allow the client to pick the size of the array to be used and allow the client to repeat the process with a new array. Use a method to calculate the standard deviation. In statistics and probability theory, the standard deviation shows how much variation or dispersion from the average exists in a group of numbers. A low standard deviation indicates that the data points tend to be very close to the mean (also called expected value); a high standard deviation indicates that the data points are spread out over a large range of values. For a finite set of numbers, the standard deviation is found by taking the square root of the average of the squared differences of the values from their average value. For example, consider a population consisting of the following eight values: 2.0, 4.0, 4.0, 4.0, 5.0, 5.0, 7.0, 9.0. These 8 data points have the mean (average) of 5.0. (2.0 + 4.0 + 4.0 + 4.0 + 5.0 + 5.0 + 7.0 + 9.0)/8.0 = 5.0.
Calculate the difference of each data point from the mean (average) and square this value.
Computers and Technology
1 answer:
Y_Kistochka [10]3 years ago
4 0

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

You might be interested in
Whereas lines of competition are clearly defined in the more established industries, in the Internet industry they are blurred a
VMariaS [17]

Answer:

C. The lines of competition are clearly defined in the more established industries, unlike the Internet where they are blurred and indistinct, as companies that compete

Explanation:

The first one is also correct, but it is a little bad for reading. D has a spelling error, and "companies competing" in B are a little blurred. All, except last, are correct. However, considering arrangements, the 'C 'option is the best.

8 0
3 years ago
Heuristics are not always completely accurate.<br><br><br> Correct or wrong?
Alisiya [41]

Answer:

They are not always right or the most accurate.

Explanation:

Judgments and decisions based on heuristics are simply good enough to satisfy a pressing need in situations of uncertainty, where information is incomplete.

8 0
3 years ago
Read 2 more answers
When widgets, or portable chunks of code, are embedded on html pages and thereby help increase the functionality of those pages,
Anna11 [10]
<span>When widgets, or portable chunks of code, are embedded on html pages and thereby help increase the functionality of those pages, consumers embrace one of the greatest virtues of social media known as Collaboration.</span>
5 0
3 years ago
A list of steps to finish a task. A set of instructions that can be performed with or without a computer is called an
fomenos

Answer:

algorithm

Explanation:

4 0
3 years ago
Suppose a local area network requires eight characters for a password. The first character must be a letter, but the remaining s
Elis [28]

Answer: 2037468266496

Explanation:

The question says first character must be a letter = A - Z ( 26 characters )

Others can either be letters or digits = digits with range 0-9 ( 10 digits )

From the second to the seventh character can either be digits or letter hence we have ( 10 +26 ) = 36 chances

Considering rule of product

Number of chances/outcomes of the password = ( 26×36⁷)

The power of 7 was as a result of remaining seven characters can be either a letter or digits.

5 0
3 years ago
Other questions:
  • Ad designers use movement in order to
    9·2 answers
  • To change a chart's data series, make the chart active, then in the data group on the chart tools design tab, click the _____ bu
    9·1 answer
  • Oxygen-18 has an atomic number of 8. How many neutrons are in this isotope?
    7·1 answer
  • A number of LC-3 instructions have an "evaluate address" step in the instruction cycle, in which a 16-bit address is constructed
    6·1 answer
  • Which of the following attacks seeks to introduce erroneous or malicious entries into a server's hostname-to-IP address cache or
    5·1 answer
  • Giving Brainliest IFFF CORRECT
    9·1 answer
  • You are required to copy in your attendees' emails from outside of Outlook when creating a meeting
    6·2 answers
  • Resumen sobre Tailandia​
    10·1 answer
  • Which of the following technologies is an example of social media
    12·1 answer
  • Can i have help for a ggogle class room
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!