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atroni [7]
4 years ago
5

A box of chalk and 2 staplers cost $10. three boxes of chalk and 2 staplers cost $18. find the total cost of 1 box of chalk and

1 stapler.
Mathematics
1 answer:
Alchen [17]4 years ago
7 0
Here is the solution of the given problem above:
Let s= staples 
<span>c = chalk</span>

<span>c + 2s = 10 </span>
<span>3c + 2s = 18 </span>

<span>-c-2s = -10 </span>
<span>3c + 2s = 18 </span>

<span>2c = 8 </span>

<span>c = 4 </span>
<span>s = 3 
</span>Therefore, the price per chalk box is $4 and per stapler is $3.
So the total cost of the chalk and stapler would be $7. 
Hope this is the answer that you are looking for. Thanks for posting it here in brainly.
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If the total cost C for p pounds of pepperoni if each pound cost 4.86
Marta_Voda [28]
Costs<span> $.59c(p) = .59p. C(p) has unit $/lbs, </span>p=<span>lbs</span>
3 0
3 years ago
Write and solve an equation to find the value of x and a missing angle in the triangle below.
Arturiano [62]

Answer:

x = 27°, ∠JLK = 55°

Step-by-step explanation:

From the diagram in the question above,

The exterior angle of a triangle is equal to the sum of the two opposite side

3x+13 = 39+(2x+1)

3x+13 = 40+2x

collect like terms and solve for x

3x-2x = 40-13

x = 27°.

∠JKL = 2x+1

Substitute the value of x

∠JKL = 2(27)+1

∠JKL = 54+1

∠JKL = 55°

5 0
3 years ago
Wats da distance between 13 and -5
levacccp [35]
You would add them together if it’s on a number line bc u have to go 5 to get to 0 then another 13 so 13+5=18
6 0
3 years ago
Read 2 more answers
Evaluate the expression
andreev551 [17]

Step-by-step explanation:

this is correct answer thank you

3 0
3 years ago
Mr. Kohl has a breaker containing n milliliters of solution to distribute to the students in his chemistry class. If he gives ea
77julia77 [94]

Answer:

There were 26 students in his class and the teacher had 83 ml of the solution.

Step-by-step explanation:

Mr. Kohl has a "x" amount of solution, if he divides it by the number of students "n" he'll give each student 3 milliliters  and have a left over of 5 milliliters. If the amount of solution Mr. Kohl had was "x + 21" then he'd be able to give each student 4 milliliters of the solution. From these informations we have:

x = 3*n + 5

(x + 21)/n = 4

x + 21 = 4*n

x = 4*n - 21

Now that we have two equations and two variables we can solve the system of equations, as seen bellow:

3*n + 5 = 4*n - 21

3*n - 4*n = -21 - 5

-n = -26

n = 26

x = 4*26 - 21 = 83 ml

There were 26 students in his class and the teacher had 83 ml of the solution.

3 0
3 years ago
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