Answer:
Step-by-step explanation:
To test the hypothesis is the mean SAT score is less than 1520 at 5% significance level
The nul hypothesis is
![H_0; \mu \geq 1520](https://tex.z-dn.net/?f=H_0%3B%20%5Cmu%20%5Cgeq%201520)
The alternative hypothesis is
![H_0 ; \mu\leq 1520](https://tex.z-dn.net/?f=H_0%20%3B%20%5Cmu%5Cleq%201520)
The test statistic is
![t=\frac{\bar x- \mu}{(\frac{s}{\sqrt{n} } )}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B%5Cbar%20x-%20%5Cmu%7D%7B%28%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%20%7D%20%29%7D)
![t= \frac{1501-1520}{(\frac{53}{\sqrt{20} } )} \\\\=-1.603](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7B1501-1520%7D%7B%28%5Cfrac%7B53%7D%7B%5Csqrt%7B20%7D%20%7D%20%29%7D%20%5C%5C%5C%5C%3D-1.603)
The t - test statistics is -1.603
The t - critical value is,
The small size is small and left tail test.
Look in the column headed
and the row headed in the t - distribution table by using degree of freedom is,
d.f = n - 1
= 20 - 1
= 19
The t - critical value is -1.729
The conclusion is that the t value corresponds to sample statistics is not fall in the critical region, so the null hypothesis is not rejected at 5% level of significance.
there is insignificance evidence ti indicate that the mean SAT score is less than 1520. The result is not statistically significant
1.12 add im an artist so i know trying to help people out
Answer:
THIS IS AN EXAMPLE:
Initial score was 80. There was an accidental 5 point deduction. This means anything that gives 85 is the correct answer.
80 + 5 = 85
80 - (-5) = 85
Step-by-step explanation:
Answer:
x+35
Step-by-step explanation:
Left to right. Whatever comes first (multiplication or division) you do. This is all part of the PEMDAS/Order of operations.
Hopefully I solved your problem! :)