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3 years ago

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Lisa can shovel snow from her driveway in 65 minutes. tom can do the same job in 55 minutes. how long would it take lisa and tom

to shovel the driveway if they worked together?

1 answer:

Paraphin [41]3 years ago

5 0

65+55=120
120÷2=60
So, it take them 60mins if they worked together.

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Solve and round to the nearest hundredth please!!!

sasho [114]

Answer:

x = 0.96

Step-by-step explanation:

$7 \times 16^{8x - 8} = 3$

$(2^4)^8(x - 1) = \dfrac{3}{7}$

$2^{32(x - 1)} = \dfrac{3}{7}$

$\log 2^{32(x - 1)} = \log \dfrac{3}{7}$

$32(x - 1)\log 2 = \log 3 - \log 7$

$(x - 1) = \dfrac{\log 3 - \log 7}{32}$

$(x - 1) = \dfrac{\log 3 - \log 7}{32\log 2}$

$x = \dfrac{\log 3 - \log 7}{32\log 2} + 1$

$x = 0.961800237...$

Answer: x = 0.96

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3 years ago

Find the third, fourth, and fifth terms of the sequence defined by

statuscvo [17]

By the recursive definition,

$a_3=2a_2-a_1=2\cdot9-4=14$

$a_4=2a_3-a_2=2\cdot14-9=19$

$a_5=2a_4-a_3=2\cdot19-14=24$

$a_6=2a_5-a_4=2\cdot24-19=29$

7 0

3 years ago

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20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

IRINA_888 [86]

<u>ANSWER: </u>

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

<u>SOLUTION: </u>

Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

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3 years ago

Help me plz I beg you

scZoUnD [109]

The answer would be C. We know that d is equal to the initial depth of a lake. The two given initial depths are 58 feet and 53 feet, so we know that one of the equations must be either d=58 or d=53. Because there only C has either one of those, d=58, we know that it must be the answer.

To find the other equation, it is just a linear function for the other lake. The y-intercept, or initial value, is 53, so in the equation y=mx+b, it is the b value. The slope, or m value, is 3 feet, so you have y=d=3x+53.

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3 years ago

There were 576 bottles of water at the snack shop. People bought 469 bottles of water. How many bottles of water are at the snac

MissTica

Answer:

107

Step-by-step explanation:

576-469=107

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3 years ago

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