3/12 = (3÷3)/(12÷3) = 1/4
Answer:
27 ft
the maximum height of the arrow is 27 ft
Step-by-step explanation:
Given;
The height of the arrow is given by the function;
h(t) = -16t^2 + 32t + 11
Maximum height is at point when dh(t)/dt = 0.
Differentiating h(t), we have;
dh/dt = -32t + 32 = 0
Solving for t;
-32t = -32
t = -32/-32 = 1
t = 1 (time at maximum height is t = 1)
Substituting t=1 into h(t), to determine the value of maximum height;
h(max)= -16(1^2) + 32(1) + 11
h(max) = 27 ft
the maximum height of the arrow is 27 ft.
Answer:
I think that is a function
Step-by-step explanation:
Answer:
plug it into the pythagorean theorem formula
Step-by-step explanation:
since the pythagorean theorem is a^2+b^2=c^2, you have to plug in the lengths of the leg and the hypotenuse to the formula. If you were trying to find a, you would plug in the second leg into b and the hypotenuse into c. so if for example you needed to find a and the second leg was 2 inches while the hypotenuse was 5 inches, the formula would be a^2+2^2=5^2. then solve it like a regular equation, so a^2+4+25, a^2=21, and you would do the square root of that answer. hope that helped.
