A₁ = 9
a₂ = 9+2 → a₂ = a₁ + 2. Since it's an AP, d, the common difference is 2
1) Then the recursive formula is :
a(n) = a(n-1) + 2
2) Explicit formula:
It's an AP, with first term a₁, d= common difference and n = number of term, which is the number of rows in this problem.
the value of the nth term is given by the formula is:
value of nth term = a₁ + (n-1).d
3) Number of seats in the 12th row:
9 + (12-1).2 = 31 seats
Y - 5 = 2/3(x + 3)
y - 5 = 2/3x + 2
y = 2/3x + 2 + 5
y = 2/3x + 7
For #6;
We know that there are 46% male students and 30% of them are seniors. This means that we have to assume that 30% of the male students are seniors and that 30% of the female students are seniors. Taking 30% of 46% gives us 13.8%.
For #7;
We are looking for the possibility that we choose a junior student (22%) or a sophomore student (28%). This adds up to 50% (22%+28% = 50%). That is out answer.
Answer:
Step-by-step explanation:
Recall that: The number of combination to select any k consecutive element from n consecutive term is given by the equation 
where:
n = 26
k = 5
Therefore, there are 26334 selection of 5 episodes with no two consecutive episodes chosen
Step-by-step explanation:
20-17+3=6
18+1-5=14
7-8+6=5
20-18+7=9
17+1-8=10
3-5+6=4
