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3 years ago

PLS HELP 25 POINTS NO CAP PLS BRAINLEIST

Mathematics

2 answers:

Oliga [24]3 years ago

7 0

Answer:

I can't see the picture or handwriting

Ne4ueva [31]3 years ago

6 0

Can’t rlly see it sorry just here to say answers btw

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What is the answer so confused

suter [353]

Cause a number cube is wack and cant solve nothin bout bowling you gotta use the numbers 6 outta 10

8 0

3 years ago

Please help needs turned in

Alecsey [184]

When you have

$4x=\dfrac{2}{5}$

you can solve the equation by multiplying both sides by 1/4. Then simplify.

$4x\cdot\dfrac{1}{4}=\dfrac{2}{5}\cdot\dfrac{1}{4}\\\\x\cdot\dfrac{4}{4}=\dfrac{2\cdot 1}{5\cdot 4}\\\\x=\dfrac{2}{20}=\dfrac{1}{10}$

4 0

3 years ago

Elsa is staining the wooden floor of a court. The court is in the shape of a rectangle. Its length is 43 feet and its width is 3

quester [9]

To find the area multiply length times width.
43 times 36 is 1548
Take 1548 divide by 172 to get the answer.
1548/172 equals 9

8 0

3 years ago

Read 2 more answers

Suppose an electronics manufacturer takes a sample of 5000 devices produced by an assembly line. Each device is inspected or tes

Deffense [45]

Answer:

DPMO = 40

Does not meet Six Sigma goals

Step-by-step explanation:

If there are 40 possible defects in each of the 5,000 devices, the number of defect opportunities is:

$n=5,000*40\\n=200,000\ opportunities$

If 8 total defects were found, the DPMO for the sample is:

$DPMO = \frac{8}{200,000}*1,000,000\\DPMO = 40$

Six Sigma aims to reduce defects to 3.4 Defects Per Million Opportunities, since the DPMO is higher than 3.4, the process does not meet Six Sigma goals.

8 0

3 years ago

What is the length of the segment, endpoints of which are intersections of parabolas y=x^2− 11/4 x− 7/4 and y=− 7/8 x^2+x+ 31/8

kobusy [5.1K]

Answer:

The length of line segment is 5

Step-by-step explanation:

we are given equation of parabolas as

$y=x^2-\frac{11}{4}x-\frac{7}{4}$

$y=-\frac{7}{8}x^2+x+\frac{31}{8}$

Firstly, we will find intersection points

we can set them equal

and then we can solve for x

$x^2-\frac{11}{4}x-\frac{7}{4}=-\frac{7}{8}x^2+x+\frac{31}{8}$

Multiply all sides by 8

$x^2\cdot \:8-\frac{11}{4}x\cdot \:8-\frac{7}{4}\cdot \:8=-\frac{7}{8}x^2\cdot \:8+x\cdot \:8+\frac{31}{8}\cdot \:8$

$8x^2-22x-14=-7x^2+8x+31$

$15x^2-30x-45=0$

now, we can factor it

$15(x^2-2x-3)=0$

$15(x-3)(x+1)=0$

$x=-1,x=3$

now, we can find y-values

At x=-1:

$y=(-1)^2-\frac{11}{4}(-1)-\frac{7}{4}$

y=2

so, we get point as

(-1,2)

At x=3:

$y=(3)^2-\frac{11}{4}(3)-\frac{7}{4}$

y=-1

so, we get point as

(3,-1)

now, we can find distance between these two points

(-1,2)

x1=-1 , y1=2

(3,-1)

x2=3 , y2=-1

now, we can find distance

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$D=\sqrt{(3+1)^2+(-1-2)^2}$

$D=5$

So,

The length of line segment is 5

6 0

3 years ago