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crimeas [40]
3 years ago
10

Help needed! Can I get some help with two questions?

Mathematics
1 answer:
Elodia [21]3 years ago
7 0

<u>Red</u>

This is a circle with center (h, k) at (0,0) and radius (r) = 6

Formula: (x - h)² + (y - k)² = r²

Answer: x² + y² = 36

***************************************

<u>Blue</u>

This is a circle with center (h, k) at (2,2) and radius (r) = 1

Formula: (x - h)² + (y - k)² = r²

Answer: (x - 2)² + (y - 2)² = 1

***************************************

<u>Green:</u>

This is a circle with center (h, k) at (-2,-2) and radius (r) = 1

Formula: (x - h)² + (y - k)² = r²

Answer: (x + 2)² + (y + 2)² = 1

***************************************

<u>Purple:</u>

This is an ellipse with center (h, k) at (0,-2) and radius on the x-axis (a) = 3 and radius on the x-axis (b) = 1

Formula: \frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}}=1

Answer: \frac{x^{2}}{9} +(y+2)^{2}=1

***************************************

<u>Black:</u>

This is a parabola with vertex (h, k) at (0,-6) and vertical stretch (a) = -1

Formula: y = a(x - h)² + k

Answer: y = -x² - 6


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\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

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$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

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To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

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