All categories

3 years ago

The number of question on an exam varies with the number

Mathematics

1 answer:

alekssr [168]3 years ago

5 0

Answer:

$t=5x$

Step-by-step explanation:

So the number of questions in an exam varies with the number of minutes to take the exam.

For each question there are 5 minutes allotted.

Lets say that there are 'x' number of questions in the exam and 't' is the total time taken to finish the exam, in minutes. So the time taken to complete the exam would be

$5 \times x=5x$

Therefore, the equation relating the time taken to complete the exam and the number of questions is given by:

$t=5x$

So there are two variables in the equation, 't', and 'x':

t - time taken to complete the exam

x - number of questions on the exam

You might be interested in

67 hundreds into standard form

Svetach [21]

There's a difference between "hundredths" and "hundreds". I'm going to assume you mean 6,700.

Answer:

6.7*10^3

Step-by-step explanation:

Write out the number.

6700

Bring the decimal to the left. However many times you move over to the left until you get between 6 & 7 should be your exponent for 10.

6.7*10^3

7 0

3 years ago

Find the slope of the line shown on the graph to the right.

Nostrana [21]

Answer:

slope=5/6

Step-by-step explanation:

m=y2-y1/x2-x1

3-(-2)=5

2-(-4)=6

5/6

hope this helps :3

if it did pls mark brainliest

6 0

3 years ago

Read 2 more answers

Measurements of the sodium content in samples of two brands of chocolate bar yield the following results (in grams):

Tpy6a [65]

Answer:

98% confidence interval for the difference μX−μY = [ 0.697 , 7.303 ] .

Step-by-step explanation:

We are give the data of Measurements of the sodium content in samples of two brands of chocolate bar (in grams) below;

Brand A : 34.36, 31.26, 37.36, 28.52, 33.14, 32.74, 34.34, 34.33, 29.95

Brand B : 41.08, 38.22, 39.59, 38.82, 36.24, 37.73, 35.03, 39.22, 34.13, 34.33, 34.98, 29.64, 40.60

Also, $\mu_X$ represent the population mean for Brand B and let $\mu_Y$ represent the population mean for Brand A.

Since, we know nothing about the population standard deviation so the pivotal quantity used here for finding confidence interval is;

P.Q. = $\frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ~ $t_n__1+n_2-2$

where, $Xbar$ = Sample mean for Brand B data = 36.9

$Ybar$ = Sample mean for Brand A data = 32.9

$n_1$ = Sample size for Brand B data = 13

$n_2$ = Sample size for Brand A data = 9

$s_p = \sqrt{\frac{(n_1-1)s_X^{2}+(n_2-1)s_Y^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(13-1)*10.4+(9-1)*7.1 }{13+9-2} }$ = 3.013

Here, $s^{2}_X$ and $s^{2} _Y$ are sample variance of Brand B and Brand A data respectively.

So, 98% confidence interval for the difference μX−μY is given by;

P(-2.528 < $t_2_0$ < 2.528) = 0.98

P(-2.528 < $\frac{(Xbar -Ybar) -(\mu_X-\mu_Y)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < 2.528) = 0.98

P(-2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ < $(Xbar -Ybar) -(\mu_X-\mu_Y)$ < 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ ) = 0.98

P( (Xbar - Ybar) - 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ < $(\mu_X-\mu_Y)$ < (Xbar - Ybar) + 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ ) = 0.98

98% Confidence interval for μX−μY =

[ (Xbar - Ybar) - 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ , (Xbar - Ybar) + 2.528 * $s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2}$ ]

[ $(36.9 - 32.9)-2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9}$ , $(36.9 - 32.9)+2.528*3.013\sqrt{\frac{1}{13} +\frac{1}{9}$ ]

[ 0.697 , 7.303 ]

Therefore, 98% confidence interval for the difference μX−μY is [ 0.697 , 7.303 ] .

4 0

3 years ago

- 4x – 4y=_8<br> x+8y = 16

Lerok [7]

Answer:x

x = − 32 /7

Step-by-step explanation:

4 0

4 years ago

If the product of the integers a, b, and c is 1, then what is the difference between the largest and the smallest possible

stepladder [879]

Since there are no multiples other than 1 and -1 that could multiply in any way to equal 1, those are the only numbers you can really work with

it is a possibility that a, b, and c could equal 1 but then it would go wrong when comes time to subtract since all numbers are equal and cannot subtract largest from smallest.

a logical approach would be to try -1, -1, and 1 since -1 * -1 = 1 and then 1* 1 =1

we can make a= -1 , b= -1, and c= 1
(we need b to equal -1 so that we get an answer of -1 opposed to if we made a=-1 and c=-1, all outcomes would equal 1)
-1²=1
-1³=-1
1⁴= 1
since 1 is the largest possible outcome and -1 is the lowest possible outcome you should subtract the two

1-(-1) = 1+1 = 2

The answer should be D: 2

hoped this helped at all!

5 0

3 years ago