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kaheart [24]
3 years ago
5

Triangle ABC is an isosceles with a base AC. The base angles are 60 degrees. Find the length of the base and the length of the a

ltitude from the vertex angle. The length of each leg is 5
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

base =5   because all angles=60, so an equilateral triangle

height=4.33

Step-by-step explanation:

height^2+1/2(5)^2=5^2

height^2+6.25=25

height^2=18.75

height=4.33

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il63 [147K]

Answer:

May be the second one

Step-by-step explanation:

hope it'll help ☺️

4 0
3 years ago
HELP ASAP PLEASE 20 POINTS
jok3333 [9.3K]

Answer:

904.4

Step-by-step explanation:

C

4 0
3 years ago
Anyone? Can help !!!
il63 [147K]

Answer:

C.g(x) = 5x²

Step-by-step explanation:

To find the equation for the function g(x), use the format for a quadratic equation. Without any up/down and left/right shifts, the form is y = ax².

Substituting "x" and "y" into the equation tells you if a point is on the graph.

"a" tells you the vertical stretch (greater than 1) or compression (greater than 0, less than 1).

In f(x) = x², a = 1 even though it's not written.

<u>Use the point (1, 5) on g(x) and substitute it</u> into the form for a quadratic function. Remember points are (x, y), so x = 1 and y = 5.

g(x) = ax²    

y = ax²       In function notation, g(x) replaces the "y". Switch it back to "y".

5 = a(1)²     Substitute x = 1 and y = 5

5 = a(1)     Solve the exponent first. (1)² = 1

5 = a         When you multiply "a" by 1, the answer is just "a".

a = 5         Solved for "a". Put variable on left side for standard formatting.

With the quadratic form, substitute "a" into g(x).

y = ax²

g(x) = 5x²

7 0
3 years ago
FIND THE RADIUS OF A CIRCLE WHO'S DIAMETER IS40 FEET
iVinArrow [24]

Answer:

40 feet

radius is half of the diameter, so the radius is half of 40

radius = diameter/2

radius = 40/2

radius=20 feet

8 0
3 years ago
Read 2 more answers
Find the ends of the major axis and foci
poizon [28]

The ends of the major axis is = (0, ± 13) and that of the foci is: (0,±5).

<h3>What is the axis and foci about?</h3>

The term 'foci' is known to be the point at which there is the coming together of light or any other kinds of electromagnetic radiation, particles, etc.

It is also seen as the point from which they seems to go apart.

\frac{x^{2} }{144} + \frac{y^{2} }{169}  = 1

\frac{x^{2} }{12^{2} } + \frac{y^{2} }{13^{2} }

Hence, major axis is = (0, ± 13)

e = \sqrt{1 -\frac{12^{2} }{13^{2} } }

= 5/13

Foci is: (0± 13 x \frac{5}{13})

Foci is: (0, ±5)

Therefore, The ends of the major axis is = (0, ± 13) and that of the foci is: (0,±5).

Learn more about foci from

brainly.com/question/26250569

#SPJ1

8 0
2 years ago
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