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3 years ago

A dilation with a scale factor of 1/3 is a reduction.

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

8 0

That's true.
That will make the thing a third of its original size.

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Will Mark Branliest!!!!!!!!!!!!!!!!!!!!! Hurry!!!!!!!!!!!!!!!!!!!!!!!! PLEASE!!!!!!!!!!!!!!!

jenyasd209 [6]

Part 1:all triangles have a measure of 180 degrees
so, 3(x+2)+35+52=180
add 35 and 52; 3(x+2) +87=180
subtract 87 from both sides; 3(x+2)= 93
divide both sides by 3; x+2=31
subtract both sides by 2; x=29
Part 2: since 3(x+2) =93, angle C is 93 degrees

5 0

3 years ago

A penguin walks 10 feet in 6 seconds, so how long does it take for a penguin to walk 45 feet ?? Plz help me its due in a couple

Nata [24]

Answer: The penguin would walk 45 feet in around 27 seconds.

Step-by-step explanation: 10 ft = 6 sec, 20ft = 12sec, 30ft = 18 sec, 40 ft = 24 sec, 5 ft = 3 sec

6 0

3 years ago

Kind people!help me please...And a detailed solution/THANKS sin^2x-0,5sin2x=0

Volgvan

This will be easier to write, and a lot easier to read, if we temporarily
use another symbol ... say, 'Q' ... to represent ' sin(2x) ' .
Here we go:

Original equation:    Q² - 0.5 Q = 0

Factor the left side:    Q (Q - 0.5) = 0

This equation is true if either factor is zero:

-- If Q=0, then sin(2x) = 0

   2x = 0°, 180°, 360°

   x = 0°, 90°, 180°

-- If (Q-0.5) = 0, then    Q = 0.5

      sin(2x) = 0.5

   2x = 30°, 150°

   x = 15°, 75°

The whole collection of solutions
between 0° and 360° :

      x = 0°, 15°, 75°, 90°, 180° .

8 0

3 years ago

An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba

sladkih [1.3K]

Answer:

(a) The probability that a randomly selected adult is either overweight or obese is 0.569.

(b) The probability that a randomly selected adult is neither overweight nor obese is 0.431.

Step-by-step explanation:

Let A = a person is over weight and B = a person is obese.

The information provided is:

An adult is considered overweight if the BMI ≥ 25 but BMI < 30.

An obese adult will have a BMI ≥ 30.

According to the range of BMI the events A and B are independent.

P (A) = 0.331 and P (B) = 0.357.

(a)

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P (A ∪ B) = P (A) + P (B) - P (A ∩ B)

= P (A) + P (B) - P (A)×P (B)

$=0.331+0.357-(0.331\times0.357)\\=0.569833\\=0.569$

Thus, the probability that a randomly selected adult is either overweight or obese is 0.569.

(b)

Compute the probability that a randomly selected adult is neither overweight nor obese as follows:

$P(A^{c}\cup B^{c})=1-P(A\cup B)=1-0.569=0.431$

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.431.

4 0

4 years ago

Domain range function?

oee [108]

Domain is x range is y

7 0

3 years ago