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Nikolay [14]
3 years ago
10

The mean incubation time for a type of fertilized egg kept at 100.7100.7â°f is 2323 days. suppose that the incubation times are

approximately normally distributed with a standard deviation of 22 daysdays. â(a) what is the probability that a randomly selected fertilized egg hatches in less than 2121 âdays? â(b) what is the probability that a randomly selected fertilized egg hatches between 1919 and 2323 âdays? â(c) what is the probability that a randomly selected fertilized egg takes over 2525 days toâ hatch?
Mathematics
1 answer:
Irina18 [472]3 years ago
5 0
In this item, we have the mean incubation period of 23 days and the standard deviation is 22 days. We use z-score to determine the unknown in each of the items.

(a) less than 21 days.
       z-score = (23 - 21) / 22 = 1/11
This translates to a percentage of 53.6%

(b) z-score for 19 days.
     z-score = (23 - 19) / 22 = 2/11
This translates to a percentage of 57.2%.
   
    z-score for 23 days.
   z-score = (23 - 23)/ 22 = 0
This translates to a percentage of 50%.

The difference between the two numbers is only 7.2%

(c) z-score of 25.
     z-score = (23 - 25)/ 22 = -1/11
This translates to a percentage of 42.3%.

Then, subtract this value from 100 to give us the final answer of 57.2%.
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ra1l [238]

Answer:

Vans - 7

Cars - 15

Step-by-step explanation:

$200 * 7 = $1400

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8 0
2 years ago
Bob made 4 1/4 pounds of fruit salad. He added 10 ounces of pineapple. How many 6-ounce servings did Bob make?
rosijanka [135]

Answer:

13 or B

Step-by-step explanation:

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6 0
3 years ago
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There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
3 years ago
7. Look at this figure
kap26 [50]

Answer:

thx for the 32 points

Step-by-step explanation:

3 0
2 years ago
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Two sides and an angle​ (ssa) of a triangle are given. determine whether the given measurements produce one​ triangle, two​ tria
Setler [38]
These are a huge pain.  First set up your initial triangle with A and B as your base angles and C as your vertex angle.  Now drop an altitude and call it h.  You need to solve for h.  Use sin 56 = h/13 to get that h = 10.8.  The rule is that if the side length of a is greater than the height but less than the side length of b, you have 2 triangles.  h<a<b --> 10.8<12<13.  Those are true statements so we have 2 triangles.  Side a is the side that swings, this is the one we "move", forming the second triangle.  First we have to solve the first triangle using the Law of Sines, then we can solve the second.  \frac{sin56}{12} = \frac{sinB}{13} to get that angle B is 64 degrees.  Now find C: 180-56-64=60.  And now for side c: \frac{sin56}{12} = \frac{sin60}{c} and c=12.5.  That's your first triangle.  In the second triangle, side a is the swinging side and that length doesn't change.  Neither does the angle measure.  Angle B has a supplement of 180-64 which is 116.  So the new angle B in the second triangle is 116, but the length of b doesn't change, either.  I'll show you how you know you're right about that in just a sec.  The only angle AND side that both change are C and c.  If our new triangle has angles 56 and 116, then C has to be 8 degrees. Using the Law of Sines again, we can solve for c:\frac{sin8}{c} = \frac{sin56}{12} and c = 2.0.  We can look at this new triangle and determine the side measures are correct because the longest side will always be across from the largest angle, and the shortest side will always be across from the smallest angle.  The new angle B is 116, which is across from the longest side of 13.  These are hard.  Ugh.

8 0
3 years ago
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