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vodka [1.7K]
4 years ago
6

Tom is hiking on a trail that lies on a railroad track. The total length of the trail is 5.4 kilometers. Starting from the begin

ning of the trail, he has been walking for 45 minutes at an average speed of 2.4 kilometers per hour. What is the length to the end of the trail?
Mathematics
2 answers:
meriva4 years ago
5 0

Welcome to Brainly!

The total trail length is 5.4 km.  If we subtract the distance already covered, the result will be the remaining distance to hike:

5.4 km - (2.4 km/hr)((3/4) hr  =  (5.4 - 1.8) km.

Tom has 3.6 km left to hike to reach the end of the trail.

Sergeu [11.5K]4 years ago
3 0
2.4 is the answer to this question
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Answer:

Each strip should 11 inches wide.

Step-by-step explanation:

We are told that Jazmin has two pieces of construction paper. The first piece is 44 inches wide and the second piece is 33 inches wide. Jazmin wants to cut the paper into strips that are equal in width and are as wide as possible.

To find the greatest possible width of each strip we will find GCF of 44 and 33.

Factors of 44 are: 1, 2, 4, 11, 22, 44.

Factors of 33 are: 1, 3,11, 33.

We can see that 11 is the greatest common factor of 44 and 33 as 11*4=44 and 11*3=33, therefore, Jasmine should cut each strip 11 inches wide.

5 0
4 years ago
Read 2 more answers
Random variables X Poisson~ ( a) ,Y Poisson ~ ( a) . X and Y are independent. If 2 1, 2 1. U =2X+ Y-1, V=2X- Y +1. Find: ) Cov (
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By definition of covariance,

\mathrm{Cov}(U,V)=E[(U-E[U])(V-E[V])]=E[UV-E[U]V-UE[V]+E[U]E[V]]=E[UV]-E[U]E[V]

Since U=2X+Y-1 and V=2X-Y+1, we have

E[U]=2E[X]+E[Y]-1

E[V]=2E[X]-E[Y]+1

\implies E[U]E[V]=(2E[X]+E[Y]-1)(2E[X]-(E[Y]-1))=4E[X]^2-(E[Y]-1)^2=4E[X]^2-E[Y]^2+2E[Y]-1

and

UV=(2X+Y-1)(2X-(Y-1))=4X^2-(Y-1)^2=4X^2-Y^2+2Y-1

\implies E[UV]=4E[X^2]-E[Y^2]+2E[Y]-1

Putting everything together, we have

\mathrm{Cov}(U,V)=(4E[X^2]-E[Y^2]+2E[Y]-1)-(4E[X]^2-E[Y]^2+2E[Y]-1)

\mathrm{Cov}(U,V)=4(E[X^2]-E[X]^2)-(E[Y^2]-E[Y]^2)

\mathrm{Cov}(U,V)=4V[X]-V[Y]=4a-a=\boxed{3a}

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4 years ago
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16/8 = 2

But -32/16 = -2.

The ratio is not constant, hence it is not a geometric.

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3 years ago
True or false: any nonzero integers, the product and the quotient have the same sign. Why?
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Hope this helped! :D
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3 years ago
Whenever a,x,y are positive integers, which of the following expressions is equivalent to x^ay^a
lilavasa [31]

Answer:

{(xy)}^{a}

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when the exponent is equal, we can put the x and y together in a bracket and a as the Exponent of xy.

Hope I get your question~

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3 years ago
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