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nasty-shy [4]
3 years ago
8

Please answer *Will give brainliest* PLEASE DO NOT EXPLAIN

Mathematics
1 answer:
seraphim [82]3 years ago
3 0

Answer:

a, c, c, d, c, c.

Step-by-step explanation:

I worked out the math

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A box of 35 cowboys crunch cookies costs $5.40 Matt has $2.25 off coupon if Matt uses his coupon what will be the price per cook
Firlakuza [10]
$0.09 per cookie

first, you subtract $2.25 from $5.40 to get $3.15.
then, you divide $3.15 by 35 and you get $0.09.

Hope this helps!(:


6 0
3 years ago
6x²-3x+8x-6 Plz do grouping for it
Nat2105 [25]

Answer:

6x^{2} +5x-6

Step-by-step explanation:

Keep 6x^{2} and group -3x+8x which becomes 5x. Then keep -6.

Then it becomes the answer above.

7 0
3 years ago
Can anyone help me this was literally due over a week ago
mixer [17]

Answer:

You multiply 5 by 1/5 to get 1. So with 2x, you multiply by 1/(2x) to get 1. That's about all you know, since we only know that x is positive.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
At an art exhibition there are 12 paintings of which 10 are original. A visitor selects a painting at random and before decides
Reika [66]

Answer:

a) 0.8333

b) 0.75

c) 0.8181 or 0.9090

Step-by-step explanation:

a)

The probability the visitor selects an authentic painting is  

10/12 = 0.8333

b)

Since the opinion of the expert does not depend on your choice, the events are <em>independent</em>, so the probability that the expert says is authentic and it really is, is

0.8333*0.9 = 0.75

c)

If the expert decides the painting is a copy and it is not, then there are 11 paintings of which 9 are authentic, so the probability the visitor selects a new original painting is

9/11= 0.8181

If the expert decides the painting is a copy and it is, then there are 11 paintings of which 10 are authentic, so the probability the visitor selects a new original painting is

10/11= 0.9090

8 0
3 years ago
Solve for x.* (4x + 7)° (6x + 3)° Sign​
Whitepunk [10]

24 x ^2 + 54 x + 21,

if you would like me to explain how to do it, I can in the comments.

3 0
3 years ago
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