Answer:
correct answer here
Step-by-step explanation:
Answer:
A) GCF = 
B) (3b + 10) = 0
C) b = 0, b = -10/3
Step-by-step explanation:
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Step-by-step explanation:
x1+x2 = (-1-√2)/3 + (-1+√2)/3
= -2/3
(x1) (x2) = (-1-√2)/3 × (-1+√2)/3
= -1/9
the equation :
x² -(-2/3)x + (-1/9) = 0
x² + ⅔ x - 1/9 = 0
Answer:
Is this a question or free kaching if it is a question what are we trying to answer. We need details
Step-by-step explanation:
