875,932,461,160 what digit is in the hundred-millions place of this number.

Probability involving choosing from objects that are not distinct

Sliva [168]

Step-by-step explanation:

No. of possible selections= 5+4+3= 12

Probability of selecting drama= 3÷12

= 1÷4

PLEASE MARK BRAINLIEST.

7 0

3 years ago

If J/24 = K, then J/6 =

tensa zangetsu [6.8K]

Answer:

4K

Step-by-step explanation:

$\frac{J}{24}$ = K ( multiply both sides by 24 to clear the fraction )

J = 24K ( divide both sides by 6 )

$\frac{J}{6}$ = 4K

8 0

3 years ago

$1,240 at 8% compounded annually for 2 years

saw5 [17]

The answer is $1,446.33. 1,240 x 8% = $99.20 $1,240 + $99.20 = $1,339.20. $1,339.20 x 8% = $107.13 $1,339.20 + $107.13 = $1,446.33. Hope I could help! :D

4 0

3 years ago

Jeff reads 5/7 of a book in 4 hours. At this rate, how much did he read in 1 hour? Please answer this correctly. Don't put a lin

leonid [27]

Answer:

Jeff read 5/28 of a book in 1 hour.

Step-by-step explanation:

The rate given is 5/7 of a book read in 4 hours.

If the questions asks how much he read in 1 hour, it means the answer needed is a unit rate.

A unit rate is a rate per unit. In this case, a rate per hour.

Let’s find how much Jeff read in 1 hour:

5/7 in 4 hours is the rate given so:

5/7 ÷ 4

= 5/7 x 1/4

= 5/28 (already simplified/final answer)

SO, Jeff read 5/28 of the book in 1 hour.

Brainliest? Hope this helped!

5 0

3 years ago

A college counselor is interested in estimating how many credits a student typically enrolls in each semester. The counselor dec

Ket [755]

Answer:

(a) The usual load is not 13 credits.

(b) The probability that a a student at this college takes 16 or more credits is 0.1093.

Step-by-step explanation:

According to the Central limit theorem, if a large sample (n ≥ 30) is selected from an unknown population then the sampling distribution of sample mean follows a Normal distribution.

The information provided is:

$Min.=8\\Q_{1}=13\\Median=14\\Mean=13.65\\SD=1.91\\Q_{3}=15\\Max.=18$

The sample size is, n = 100.

The sample size is large enough for estimating the population mean from the sample mean and the population standard deviation from the sample standard deviation.

So,

$\mu_{\bar x}=\bar x=13.65\\SE=\frac{s}{\sqrt{n}}=\frac{1.91}{\sqrt{100}}=0.191$

(a)

The null hypothesis is:

H₀: The usual load is 13 credits, i.e. μ = 13.

Assume that the significance level of the test is, α = 0.05.

Construct a (1 - α) % confidence interval for population mean to check the claim.

The (1 - α) % confidence interval for population mean is given by:

$CI=\bar x\pm z_{\alpha/2}\times SE$

For 5% level of significance the two tailed critical value of z is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Construct the 95% confidence interval as follows:

$CI=\bar x\pm z_{\alpha/2}\times SE\\=13.65\pm (1.96\times0.191)\\=13.65\pm0.3744\\=(13.2756, 14.0244)\\=(13.28, 14.02)$

As the null value, μ = 13 is not included in the 95% confidence interval the null hypothesis will be rejected.

Thus, it can be concluded that the usual load is not 13 credits.

(b)

Compute the probability that a a student at this college takes 16 or more credits as follows:

$P(X\geq 16)=P(\frac{X-\mu}{\sigma}\geq \frac{16-13.65}{1.91})\\=P(Z>1.23)\\=1-P(Z$

Thus, the probability that a a student at this college takes 16 or more credits is 0.1093.

3 0

3 years ago

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