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Cerrena [4.2K]
3 years ago
6

Which transformation(s) were used to go from the parent graph (red) to the transformed graph (blue)? Check all that apply!

Mathematics
1 answer:
UNO [17]3 years ago
3 0
<h3>2 Answers: </h3><h3>Choice B) Shift down</h3><h3>Choice C) Shift right</h3>

===================================================

Explanation:

Start with the point (-2,-4). Let's try to move it to (2, -9)

To do so, we need to shift down and to the right (in either order).

Specifically we shift 4 units to the right to go from x=-2 to x=4

Note how x=-2 moves to x+4 = -2+4 = 2

Also, we shift 5 units down. We have y = -4 turn into y = -9 as shown below

y ---> y-5 = -4-5 = -9

So the translation rule is (x,y) \to (x+4,y-5)

Let's see what happens when we apply the translation rule to (2,4)

(x,y) \to (x+4, y-5)\\\\(2,4) \to (2+4, 4-5)\\\\(2,4) \to (6, -1)\\\\

which is the other endpoint of the blue segment. This shows that the translation rule works for (2,4) to move to (6,-1)

We do not apply any dilations. The red and blue segments are the same length because translations preserve distance. All we're effectively doing is moving the red segment to land on the blue segment. This means no vertical or horizontal stretches are done. The same can be said about compressions as well.

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Each day a commuter takes a bus to work, the transportation system has a phone app that tells her what time the bus will arrive.
Paraphin [41]

Answer:

Step-by-step explanation:

Hello!

The commuter is interested in testing if the arrival time showed in the phone app is the same, or similar to the arrival time in real life.

For this, she piked 24 random times for 6 weeks and measured the difference between the actual arrival time and the app estimated time.

The established variable has a normal distribution with a standard deviation of σ= 2 min.

From the taken sample an average time difference of X[bar]= 0.77 was obtained.

If the app is correct, the true mean should be around cero, symbolically: μ=0

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H₁:μ≠0

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c.

Z_{H_0}= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } }

Z_{H_0}= \frac{0.77-0}{\frac{2}{\sqrt{24} } }= 1.89

d. This hypothesis test is two-tailed and so is the p-value.

p-value: P(Z≤-1.89)+P(Z≥1.89)= P(Z≤-1.89)+(1 - P(Z≤1.89))= 0.029 + (1 - 0.971)= 0.058

e. 90% CI

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I hope this helps!

4 0
3 years ago
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Answer:

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4 years ago
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Answer:

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I'm not sure what the answers mean.

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