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Cerrena [4.2K]
3 years ago
6

Which transformation(s) were used to go from the parent graph (red) to the transformed graph (blue)? Check all that apply!

Mathematics
1 answer:
UNO [17]3 years ago
3 0
<h3>2 Answers: </h3><h3>Choice B) Shift down</h3><h3>Choice C) Shift right</h3>

===================================================

Explanation:

Start with the point (-2,-4). Let's try to move it to (2, -9)

To do so, we need to shift down and to the right (in either order).

Specifically we shift 4 units to the right to go from x=-2 to x=4

Note how x=-2 moves to x+4 = -2+4 = 2

Also, we shift 5 units down. We have y = -4 turn into y = -9 as shown below

y ---> y-5 = -4-5 = -9

So the translation rule is (x,y) \to (x+4,y-5)

Let's see what happens when we apply the translation rule to (2,4)

(x,y) \to (x+4, y-5)\\\\(2,4) \to (2+4, 4-5)\\\\(2,4) \to (6, -1)\\\\

which is the other endpoint of the blue segment. This shows that the translation rule works for (2,4) to move to (6,-1)

We do not apply any dilations. The red and blue segments are the same length because translations preserve distance. All we're effectively doing is moving the red segment to land on the blue segment. This means no vertical or horizontal stretches are done. The same can be said about compressions as well.

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A manufactured lot of buggy whips has 20 items, of which 5 are defective. A random sample of 5 items is chosen to be inspected.
dimulka [17.4K]

Answer:

a. 39.55%

b. 44.02%

Step-by-step explanation:

We have the following data:

n = 5

x = 1

p = 5/20 = 0.25

to. If the sampling is done with replacement.

We apply the binomial distribution formula, which is as follows:

P = nCx * (p ^ x) * ((1-p) ^ (n-x))

Where nCx, is a combination, and is equal to:

nCx = n! / x! * (n-x)!

replacing we have:

5C1 = 5! / 1! * 4! = 5

replacing in the main formula:

P = 5 * (0.25 ^ 1) * ((1- 0.25) ^ (5-1))

P = 0.3955

that is, without replacing the probability is 39.55%

b. if the sampling is done without replacement.

Here it is a little different from the previous one, but what you should do is calculate three cases,

the first was the one at point a, when n = 5 and x = 1

5C1 = 5! / 1! * 4! = 5

the second is when n = 20 and x = 5, this is all possible scenarios.

20C5 = 20! / 5! * 15! = 15504

and the third is when n = 15 (20-5) and x = 4 (5-1), which corresponds to the cases when none were damaged

15C4 = 15! / 4! * 11! = 1365

In the end, it would be:

P = (5C1 * 15C4) / 20C5

Replacing:

P = 5 * 1365/15504

P = 0.4402

Which means that without replacing the probability is 44.02%

7 0
3 years ago
What is 5.476 rounded to the hundredths
ddd [48]
5.476 rounded to the hundrdths is 

5.48
7 0
3 years ago
Read 2 more answers
Someone plz help with this!
Murljashka [212]

Answer:

15x-2+7x+4=90°[being complementary angle]

22x+2=90°

22x=90°-2

22x=88

x=88/22

x=4

8 0
3 years ago
Please please help me I can figure this out :-,(
LenaWriter [7]

It's around 255

I hope this helps

7 0
3 years ago
Solve each equation or formula for the variable specified. <br><br> 5g+h=h, for g
Vlada [557]

Answer: hope this will help you

Step-by-step explanation:

Plz mark me as brainlist

8 0
3 years ago
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