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Cerrena [4.2K]
3 years ago
6

Which transformation(s) were used to go from the parent graph (red) to the transformed graph (blue)? Check all that apply!

Mathematics
1 answer:
UNO [17]3 years ago
3 0
<h3>2 Answers: </h3><h3>Choice B) Shift down</h3><h3>Choice C) Shift right</h3>

===================================================

Explanation:

Start with the point (-2,-4). Let's try to move it to (2, -9)

To do so, we need to shift down and to the right (in either order).

Specifically we shift 4 units to the right to go from x=-2 to x=4

Note how x=-2 moves to x+4 = -2+4 = 2

Also, we shift 5 units down. We have y = -4 turn into y = -9 as shown below

y ---> y-5 = -4-5 = -9

So the translation rule is (x,y) \to (x+4,y-5)

Let's see what happens when we apply the translation rule to (2,4)

(x,y) \to (x+4, y-5)\\\\(2,4) \to (2+4, 4-5)\\\\(2,4) \to (6, -1)\\\\

which is the other endpoint of the blue segment. This shows that the translation rule works for (2,4) to move to (6,-1)

We do not apply any dilations. The red and blue segments are the same length because translations preserve distance. All we're effectively doing is moving the red segment to land on the blue segment. This means no vertical or horizontal stretches are done. The same can be said about compressions as well.

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Using the given points, determine the slope. (0, 32) and (100, 212)
Lerok [7]

Slope = (y2 - y1)/(x2 - x1)

Slope = (212 - 32)/(100 - 0)

Slope = 180 / 100

Slope = 18/10

Slope = 9/5

Answer

D. slope = 9/5



4 0
3 years ago
In a class of 50 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose
Tems11 [23]

Answer:  3

Step-by-step explanation:

Let E be the event of that student pierces ear and N be the event of that student pierces nose.

Given: n(E\cup N=50)

n(E)=46\\\\n(N)=7

For any two event A and B, we have

n(A\cup B)=n(A)+n(B)-n(A\cap B)

Similarly , n(E\cup N)=n(E)+n(N)-n(E\cap N)

50=46+7-n(E\cap N)\\\\\Rightarrow\ n(E\cap N)=53-50=3

Hence, 3 students have piercings both on their ears and their noses.

7 0
3 years ago
Rewrite quadratic equation<br> -×^2+2x-10
Lostsunrise [7]
It has no solution because it is not factorable 
6 0
3 years ago
Read 2 more answers
Value of the derivative of g(x)=8-10Cosx at 'x=0' is?
VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

<u>Pre-Calculus</u>

  • Unit Circle

<u>Calculus</u>

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  • Derivative Property: \frac{d}{dx} [cf(x)] = c \cdot f'(x)
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Step-by-step explanation:

<u>Step 1: Define</u>

g(x) = 8 - 10cos(x)

x = 0

<u>Step 2: Differentiate</u>

  1. Differentiate [Trig]:                    g'(x) = 0 - 10[-sin(x)]
  2. Simplify Derivative:                   g'(x) = 10sin(x)

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em>:                    g'(0) = 10sin(0)
  2. Evaluate Trig:                      g'(0) = 10(0)
  3. Multiply:                               g'(0) = 0
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OT + 7<br> E-<br> Write the number in the form a + bi
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Use photomath and math away it help a lot.

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These apps helped me so much!! my grades went up with these apps!! :D

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