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Black_prince [1.1K]
4 years ago
14

Conversion of Celsius to Fahrenheit: F = 9/5C + 32, if C = -10

Mathematics
2 answers:
Schach [20]4 years ago
5 0

F = 9/5(-10) + 32


F = -90/5 + 32


F = -18 + 32


F = 14

yawa3891 [41]4 years ago
4 0
The answer to your question is F=14
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Jermaine did this work to solve an equation. Did he make an error?
Dahasolnce [82]

Answer:

Top right answer

Step-by-step explanation:

He added the -x to 4x when he should have subtracted.

8 0
3 years ago
Mrs.Giblin begins hiking at mile marker 25 on the Appalachian Trail and hikes 3 miles every hour. What is the slope?
Ilya [14]

Answer:

3 miles

Step-by-step explanation:

Slope is simply the change in position per unit rate. We could conclude that the steepness of the Applachian is the rate of change in position per unit time. Since the distance hiked on the Applachian is said to be 3 miles per hour, then we can conclude that the slope of the applachian is 3 miles

This is the change in miles / change in time.

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7 0
3 years ago
A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

4 0
3 years ago
Please help. -----------------------------------------
Contact [7]

Answer:

D

Step-by-step explanation:

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3 0
3 years ago
A communications company has developed three new designs for a cell phone. To evaluate consumer response, a sample of n = 120 co
defon

Answer:

The answer is "Its results are not consistent with its three designs Yes. Its results show significant differences between both the three designs."

Step-by-step explanation:

Following are the distribution of preference:  

Design 1 =54 \\\\ Design 2=38 \\\\\ Design 3=28 \\\\

Design \ \ \ \ \ \ \ \ \ \ O_i \\ 1 \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ 54 \\2  \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ 38\\3 \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \  28 \\Total \ \ \ \ \ \ \ \ \ \ 120

An expected frequency(E_i) has 40 Null hypotheses to take n=120.to each design:  

The effects of the three designs are standardized  

Inaccurate.  

Hypothesis Alternative:  

The effects of the three prototypes are not uniform

Degrees Of freedom =(n-1)=(3-1)=2

H_o, x^2  \ test\  statistic \  \sum_i {\frac{(O_i -E_i)^2}{E_i}} \\

= \frac{(54 -40)^2}{40}+\frac{(38-40)^2}{40} + \frac{(28-40)^2}{40}\\\\=49+0.1+3.6\\\\=8.6

Chi-squared distribution critical value at \alpha = 0.05 (x^2 _{0.052})=5.99  

Since x^2, a value > x^2 -table of \alpha =0.05 =5.99is determined.  

SoH_o is rejected.

4 0
3 years ago
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