Answer:
(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)
Here we have the equation:
We can rewrite this as:
Now we can add and subtract cos^2(x)*sin^2(x) to get:
We can complete squares to get:
and we know that:
cos^2(x) + sin^2(x) = 1
then:
This is the closest expression to what you wrote.
We also know that:
sin(x)*cos(x) = (1/2)*sin(2*x)
If we replace that, we get:
Then the simplification is:
Answer with Step-by-step explanation:
We are given that
F=<0,-8>=0i-8j=-8j
The component of force is divided into two direction
1.Along the plane
2.Perpendicular to the plane
1.The vector parallel to the plane will be=
By using 
Force along the plane will be=
Force along the plane will be =
N
By using 
Therefore, force along the plane=
2.The vector perpendicular to the plane=
The force perpendicular to the plane=
The force perpendicular to the plane=
N
Therefore, 
Sum of two component of force=
Sum of two component of force=
Hence,sum of two component of forces=Total force.
Answer:
The two triangles are related by Side-Side-Side (SSS), so the triangles can be proven congruent.
Step-by-step explanation:
There are no angles that can be shown to be congruent to one another, so this eliminates all answer choices with angles (SSA, SAS, ASA, AAA, AAS).
This leaves you with either the HL (Hypotenuse-Leg) Theorem or SSS (Side-Side-Side) Theorem. We could claim that the triangles can be proven congruent by HL, however, we aren't exactly sure as to whether or not the triangles have a right angle. There is no indicator, and in this case, we cannot assume so.
This leaves you with the SSS Theorem.
Answer:
No
Step-by-step explanation:
The square root of 34 does not multiply by itself
On your calculator, use the normalcdf() function, enter the Lower Limit, Upper Limit, Mean, and Standard deviation.
The mean and standard deviation are given to you. You want to find "less than 13.5 seconds", meaning that 13.5 is the maximum "Upper Limit" and 0 would be the Lower Limit because we can pretend 0 second is the minimum. Don't worry about negatives, in this scenario, values like "-5 seconds" are impossible.
Enter normalcdf(0, 13.5, 13.56, 2.24) in a calculator and the output result is the answer.
