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snow_lady [41]
3 years ago
5

58.21 + ( -139.58 ) Do I do KCO?

Mathematics
2 answers:
Daniel [21]3 years ago
5 0

Answer:

2136

Step-by-step explanation:

Alborosie3 years ago
5 0
2136 and yes you do
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2. The net of a square pyramid and its dimensions are shown in the diagram.
vovangra [49]

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Step-by-step explanatio............................................

3 0
3 years ago
Six identical square pyramids can fill the same volume as a cube with the same base. If the height of the cube is h units, what
Rus_ich [418]

Answer:

I believe "The height of each pyramid is one-half h units"

4 0
3 years ago
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Which describes the graph of y= -(x + 6)² + 6?
Eddi Din [679]

Answer:

A

Step-by-step explanation:

Since x has a negative coefficient, the graph opens downwards meaning that it has a maximum.

The vertex formula is y = a(x - h)^2 + k so the coordinate must be (-6, 6).

4 0
2 years ago
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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

8 0
3 years ago
brainlist for comeing to this question but you have to be smart or you have to get my question 5.I have two question what do you
____ [38]

Answer #1:

the difference between the PARIMITER and AREA of a shape is

  - PARIMITER is the length of all sides in total

  - AREA is the square ore cubic measurement aka VOLUME of a shape

Answer #2:

the difference between 1in and 2in is 1 in

Step-by-step explanation:

#1:

say we have a square that is 2 by 3 units, to measure the shape in both mediums we will use two easy functions

  ~ PARIMITER = 10

to figure out the outside edge of this shape, we need to measure all single sides and add them together

(2 + 2) + (3 + 3) = 4 + 6 = 10

       ^  note: be sure to add BOTH sides even if they have same measurements, beings there are two sides that have a measurement of 2 units, we add them together, same with the sides of 3, then we add those together

  ~ AREA = 6

to find the area, we just need to take ONE of each axis side (ei only left or right, top or bottum, and in some cases front or back) and lay them as shown

width = 2

height = 3

then we multiply them with each other

2 * 3 = 6

#2

finding the difference between two numbers can be quite easy, all we do is subtract 1 from the other, and depending on the result, we can tell whats greater, lesser or indifferent, take a look here

say we subtract 2in from 1in

2in - 1in = 1in

we are left with 1in from the 2in, meaning that 2in is greater then 1in by 1in, HOWEVER if we subtract 2in from 1in

1in - 2in = (-1in)

the number is in the negative, meaning that there is 1in LESS in 1in then in 2in

NOTE sometimes we find out that one of has no difference or is the same as the other number, heres an example

3in - 3in = 0in

this equation represents that the first 3in is no greater, nor lesser then the second 3in, meaning both values are the same

PS: for real though i know these are easy questions but i figured id earn the crown hehe :3, feel free to fact check this if you want, and if you want to use this as foot notes for your work

3 0
2 years ago
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