Answer:
Perimeter of sector is 47.93 cm which is greater than 47.5 cm
Step-by-step explanation:
Mathematically, the perimeter of a sector is length of the arc plus 2 radii
The length of the arc is;
theta/360 * 2 * pi * r
where theta is the angle subtended by the arc at the center of the circle
Thus, we have
135/360 * 2 * 22/7 * 11 = 25.93
Add 2 radii = 25.93 + 2(11) = 47.93 cm
This is greater than what we are asked to calculate and thus we have shown what we are asked to show
Jaime is incorrect, the angle does not depend on the radius of the circles.
<h3>Is Jaime correct?</h3>
Remember that an angle that defines an arc on a circle, does not depend on the radius of the circle.
So, if we have an angle with a measure of π/3 radians in a circle with a radius of 3 inches and an angle with a measure of π/3 radians in a circle with a radius of 6 inches, these two angles are exactly the same thing.
The radius of the circle only has an impact on the length of the arc defined by the angle.
So Jaime is clearly incorrect.
If you want to learn more about angles:
brainly.com/question/17972372
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Answer:
97
Step-by-step explanation:
Given the following conditions :
board measuring 1x100, each square is numbered from 1 to 100
Three colors are used to paint the squares from left to right in the sequence :
one blue, two reds and three green squares in a repeated pattern.
What is the highest numbered square that is painted blue?
The sequence of painting is repeated after :
(1 + 2 + 3) = 6 successive squares
Since the number of squares = 100
Maximum complete repetition possible :
100 / 6 = 16 remainder 4
Hence 16 * 6 = 96 (the highest complete sequence terminates on the square numbered 96)
On the 97th square, another sequence begins which is a blue and the 100th square is painted the first of the 3 green colors.
Hence, the highest numbered square that is painted blue is 97
The answer is (-7r-6s)/3s
89 squared. The hypotenuse is equal to 9.434 which is 89 squared.