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juin [17]
3 years ago
10

PLEASE ANSWER THIS TYSM

Mathematics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

what is the question?

Step-by-step explanation:

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Approximtely how many 27cubic volume cabinets will a container98,000cbic volume hold?
babymother [125]

Answer: 3630

Step-by-step explanation:

Given that:

Volume of container = 98,000 cubic volume

Volume of cabinet = 27 cubic volume

The number of cabinets which the container will. Hold equals:

Volume of container / volume of cabinet

= 98000 cubic volume / 27 cubic volume

= 3629.6296

The container will hold approximately 3630 27 cubic volume of cabinet.

5 0
3 years ago
Find the radius of a right cylinder with a volume of 350 cubic feet and a height of 4 feet. Round your answer to the nearest hun
frosja888 [35]

Answer:

Radius=\sqrt{27.87} feet

Step-by-step explanation:

Volume of a right cylinder= \pi *r^2*h

Volume= 350 feet^3

Height(h)=4 feet

As, \pi =\frac{22}{7}=3.14

           350=3.14*r^2*4\\\\350=12.56*r^2\\\\r^2=350/12.56\\\\r^2=27.87\\\\r=\sqrt{27.87}feet

Radius=\sqrt{27.87} feet

4 0
3 years ago
There are 2.5 centimeters in an inch. If a paperclip is 1.5 inches long, how many centimeters long is the paperclip?
Alex_Xolod [135]
For the answer to the question if t<span>here are 2.5 centimeters in an inch and if a paperclip is 1.5 inches long, how many centimeters long is the paperclip.

The answer to this question is the paperclip is </span> 3.81 cm long.

I hope my answer helped you. Have a nice day!
6 0
3 years ago
-8x-2y=-22<br> 16x+7y=17
Nataly [62]
2(-8x-2y=-22)
16x+7y=17

-16x-4y=-44
16x+7y=17

3y=-27
y=-9

16x+7(-9)=17
16x+-63=17
16x=80
X=5
5 0
3 years ago
If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

 =-a^2 (since tanA=a given )

Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
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