13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
<u>Step-by-step explanation:</u>
Total mass of acid required= 85 ounces
Let the mass of 72% acid be 'a'
Let the mass of 25% acid be 'b'
a + b = 85
b = 85-a
85(40/100) = a(72/100) + b(25/100)
85(2/5) = a(72/100) +(85- a) (25/100)
34 = (72a/100) + (2125/100) - (25a/100)
34 - (2125/100) = (72a + 25a) /100
(3400-2125)/100 = 97a /100
97a = 1275
a = 13.15 ounces
b = 85 - 13.14
b = 71.85 ounces
13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed
Answer:
ikr I feel your pain lol its trash
89235578 / 476589= 187.23 ; ( 187 times ) ;
(22,12) m=4
y=mx+b
12=4*22+b
12=88+b
subtract 88 from each side
b=-76
y = 4x-76
subtract 4x from each side
-4x+7 = -76
Choice A
You can plug in any values that make the equation true, and then plot the ordered pair.
I chose (3,1) and (6,4)
1 = 3-2
4=6-2
Plot the two ordered pairs and connect the dots to draw a line.