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katrin2010 [14]
4 years ago
9

Let g(x) be the reflection of f(x) = x 2 + 3 in the x-axis. What is the function rule for g(x)?

Mathematics
2 answers:
nevsk [136]4 years ago
3 0
G(x) will be g(x)=-2x-3 because it is a reflection of f(x) over the x-axis. F(x)'s reflection over the x-axis will become -f(x).
taurus [48]4 years ago
3 0

Answer:

g(x)=-x^2-3

Step-by-step explanation:

The parent function is x^2+3

Now, the function g(x) is obtained by reflecting the graph of f(x) about the x-axis.

When the parent function f(x) is reflected about the x-axis then the translated function is -f(x)

Therefore, we have g(x)=-f(x)

Hence, the equation of g(x) is

g(x)=-f(x)\\\\g(x)=-(x^2+3)\\\\g(x)=-x^2-3

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slava [35]

Answer:

88 is a solution to 1/8 x =11, since a solution means that x is equal to that number, so in this scenario, x=88. When substituted(88*0.125), the same answer, 11, is obtained.

Step-by-step explanation:

8 0
3 years ago
Use the graph to answer the questions help!
max2010maxim [7]

Answer:

0; 2; 6; 0 or -1

Step-by-step explanation:

If the question says "f(a)=" they are asking for the y value with the given x such as the two first ones.

If it's "f(x)=a than x=" they are asking you what x is when the (bolded) x is a given value.

5 0
3 years ago
A simple impact crater on the moon has a diameter of 15 kilometers. a complex impact crater has a radius of 30 kilometers. how m
timurjin [86]
The general equation for computing the circumference of a circle is C=\pi d, where C is the circumference, and d is the diameter. (You might also see the equation as C=2 \pi r where r is the radius, because d=2r)

Computing the circumferences of the two circles, we get:
C_{d=15}=\pi (15)=15\pi
C_{d=30}=\pi (30)=30\pi.

To calculate the ratio of two numbers, we can divide one by the other. You can look at this as "How many times does the denominator fit in the numerator?"
\frac{C_{d=30}}{C_{d=15}}=\frac{30\pi}{15\pi}=2
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7 0
4 years ago
The solution set for <br> 6a^2-a-5=0
Alex_Xolod [135]

Answer:

a=1 or a=5/6

Step-by-step explanation:

I'm going to attempt to factor 6a^2-a-5

a=6

b=-1

c=-5

Find two numbers that multiply to be a*c and add to be b.

a*c=-30                                   =-6(5)

b=-1                                          =-6+5

So replace -a with -6a+5a in the expression we started with

6a^2-6a+5a-5

now we factor by grouping

6a(a-1)+5(a-1)

(a-1)(6a-5)

Now let's solve the equation:

(a-1)(6a-5)=0

So a=1 or a=5/6

4 0
4 years ago
I need help with all of them and if you can't help with all of them just answer one of them please. Look at the picture
likoan [24]
All you have to do is substitute the y value from the 1st equation into the second equation and solve...

a) y= 2-x
5x + 4y = 5

Substitute (2-x) into the second equation anywhere there is a y...

5x + 4y = 5
5x + 4(2-x) = 5

Now solve

5x + 8 - 4x = 5
5x - 4x + 8 = 5
x + 8 = 5
x = -3

Now that you have a solution for x, substitute -3 into either of the original equations anywhere there is an x then solve for y...

y = 2 - x
y = 2 - (-3)
y = 2+3 = 5

You solved for x and got -3 and solved for y and got 5, so your solution set is
(-3, 5).

Now check it by substituting both numbers into one of the original equations and you should have a true statement if it is correct...

y = 2 - x
5 = 2 - (-3)
5 = 2+3
5 = 5

True statement... it checks!


note* during the check, if the equation would have worked out to something like 2 = 5, then that is a false statement therefore the solution set would be wrong and you'd have to go back and find the mistake.
5 0
3 years ago
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