we won´t have any triangle with these measures.
law of cosines.
a²=b²+c²-2bc(cosФ)
Data:
a=1
b=2
A=31º
Therefore:
1²=2²+c²-4c(cos 31º)
c²-(4cos 31º)c+3=0
4cos 31º≈3.43
We have to solve this equation, and find out the number of solutions:
c=[4cos 31º⁺₋√(11.756-12)]/2=
c=(4cos 31º⁺₋√(-0.244)/2
Because we have the square root of a negative number, we don´t have any possible solutions, that is to say , there are not real solutions for this equation.
Answer: We don´t have any triangle with these measures.
Answer:
M = Log (10S/S)
Step-by-step explanation:
We are told that the magnitude, M, of an earthquake is defined to be;
M = Log l/S
Where I is intensity and S is standard earthquake.
Now, we want to find the magnitude of an earthquake that is 10 times more intense than a standard earthquake
Since 10 times more intense than standard earthquake, it means that;
I = 10S
So plugging in 10S for I in the original equation for magnitude gives;
M = Log (10S/S)
I think the answer is $113.1. The question was confusing so sorry if it’s wrong.
(x+3,y-4) would be the translation of the ordered pairs
Answer: to go about this problem the easiest way for me would be to see what I can multiply to get 81. Imminently I see that 9*9 is 81 and it also adds up to 18 :)
so the answer is 9 and 9 give me a thumbs up if this helped!