Answer:
<h3>its so hard im sorry i can't answer it</h3>
a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
Answer:
Step-by-step explanation:
what math is this?
Answer:
275 miles in 5 hours
55 miles in one hour
Check
to check if im right
275×2 would be how many miles she drove in 10 hours rght ? 275×2=550
550 miles in 10 hours
we know one hour is 55 miles & 5 hours is 275 & 10 hours is 550
10 hours plus 3 hours = 13 hours right ?
55 ×3 = 165
550 +165=715
715 miles in 13 hours
Step-by-step explanation:
715÷13 to get how many miles she drove in one hour .
=55 miles in 1 hour .
then multiply 55 ×5 to get how many miles she drove in 5 hours
55×5=275
275 miles in 5 hours
Yes............................................
