All categories

3 years ago

Please help ...........

Mathematics

1 answer:

sammy [17]3 years ago

7 0

Answer:

Angle B = 80°

see attachment......

You might be interested in

I NEED HELP PLEASE!!

Anna71 [15]

Answer:

m = 2

Step-by-step explanation:

take 2 pairs from x

choose (1,5) and (2,7)

it will be m = 5 - 7

and in the bottom 1 - 2 it's a fraction

m = -2/-1

the numerator and denominator can't be both negative

so your answer is m= +2

m= slope

rate of change= slope

7 0

2 years ago

erika has 3 pieces of ribbon.each piece id 25 yards long.she needs to cut pieces that are 22 inches long.what is the greatest nu

OlgaM077 [116]

There is 900in in 25 yards so 900*3=2700/22=122.7
so it will be 122 pieces

6 0

3 years ago

Determine if the figures below are congruent? Explain why or why not. I need it for a test please answer fast!

Rus_ich [418]

Answer:

Yes they should be congruent ones just at a different angle.

Step-by-step explanation:

6 0

3 years ago

Ben is standing 8 feet from

never [62]

Answer:

Approximately 15.05 ft

Step-by-step explanation:

You need to use tangent for this question.

Since tan θ = $\frac{Opposite}{Adjacent}$

to find the Opposite, we need to rearrange the equation to:

Adjacent × tan θ = Opposite.

So if you insert 62 for θ and 8 feet for Adjacent, you will get:

8 × tan(62) = Opposite.

and you will get approximately 15.05 feet for your Opposite side

5 0

3 years ago

Graph y = x2 + 2. Identify the vertex of the graph. Tell whether it is a minimum or maximum. (0, 2); maximum (0, 2); minimum (2,

miskamm [114]

Answer:

$(0,2)$ ; minimum

Step-by-step explanation:

Given:

The function is, $y=x^{2}+2$

The given function represent a parabola and can be expressed in vertex form as:

$y=(x-0)^{2}+2$

The vertex form of a parabola is $y=(x-h)^{2}+k$ , where, $(h,k)$ is the vertex.

So, the vertex is $(0,2)$ .

In order to graph the given parabola, we find some points on it.

Let $x=-2,y=(-2)^{2}+2=4+2=6$

$x=-1,y=(-1)^{2}+2=1+2=3$

$x=0,y=(0)^{2}+2=0+2=2$

$x=2,y=(2)^{2}+2=4+2=6$

$x=1,y=(1)^{2}+2=1+2=3$

So, the points are $(-2,6),(-1,3),(0,2),(1,3),(2,6)$ .

Mark these points on the graph and join them using a smooth curve.

The graph is shown below.

From the graph, we conclude that at the vertex $(0,2)$ , it is minimum.

8 0

3 years ago

Please help ...........​

Please help ...........