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3 years ago

11

Hannah's school hosted a book donation. There are 150 students at her school, and they donated a total of b books! Hannah donate

d 3 times as many as the average number of books each student donated. How many books did Hannah donate?

1 answer:

Tcecarenko [31]3 years ago

6 0

Answer:

3*(b/50)=b/50

Step-by-step explanation:

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Answer a and b ASAP

melomori [17]

Answer:

The area of the rectangle is 48cm2

6 0

3 years ago

Please help!!!!!!!!!!!!!

ahrayia [7]

Answer:

Scenario 1 represents a greater speed

Step-by-step explanation:

scenario 1 - find equation of line on graph to compare

- use the points given to find the slope

rate = slope = (y2-y1)/(x2-x1) = (240-60)/(4-1) = 60

y intercept = 0

line equation -> y = 60x

for every mile, 60 miles are traveled

scenario 2 - interpret the equation

for every mile, 50 miles are traveled

Scenario 1 represents a greater speed

7 0

3 years ago

The sum of two numbers is 12, their product is 96. Compute these two numbers. Explain.

Anni [7]

Answer:

The numbers are

$6+2\sqrt{15}i$ and $6-2\sqrt{15}i$

Step-by-step explanation:

Let

x and y -----> the numbers

we know that

$x+y=12$ -----> $y=12-x$ ------> equation A

$xy=96$ ----> equation B

substitute equation A in equation B and solve for x

$x(12-x)=96\\12x-x^{2}=96\\x^{2} -12x+96=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} -12x+96=0$

so

$a=1\\b=-12\\c=96$

substitute

$x=\frac{-(-12)(+/-)\sqrt{-12^{2}-4(1)(96)}} {2(1)}$

$x=\frac{12(+/-)\sqrt{-240}} {2}$

Remember that

$i^{2}=\sqrt{-1}$

$x=\frac{12(+/-)\sqrt{240}i} {2}$

$x=\frac{12(+/-)4\sqrt{15}i} {2}$

Simplify

$x=6(+/-)2\sqrt{15}i$

$x1=6+2\sqrt{15}i$

$x2=6-2\sqrt{15}i$

we have two solutions

<u><em>Find the value of y for the first solution</em></u>

For $x1=6+2\sqrt{15}i$

$y=12-x$

substitute

$y1=12-(6+2\sqrt{15}i)$

$y1=6-2\sqrt{15}i$

<u><em>Find the value of y for the second solution</em></u>

For $x2=6-2\sqrt{15}i$

$y2=12-x$

substitute

$y2=12-(6-2\sqrt{15}i)$

$y2=6+2\sqrt{15}i$

therefore

The numbers are

$6+2\sqrt{15}i$ and $6-2\sqrt{15}i$

8 0

4 years ago

Find a quadratic equation with integer coefficients that has the following solution set of {4,4/5}

schepotkina [342]

(x-4)(x-4/5)

Hope this helped!

4 0

4 years ago

17<br> Solve for x and round your answer to the Nearest Tenth.<br> 4 A<br> 6

Gekata [30.6K]

Answer:

x=12

Step-by-step explanation:

cause then when u add them it's bigger than 17

6 0

3 years ago