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julsineya [31]
3 years ago
14

PLEASE HELP ME ON GEOMETRY QUESTIONS!!!!!!! 100 POINTS!!

Mathematics
1 answer:
aniked [119]3 years ago
4 0

2. Equality created by an angle bisector. An angle bisector creates 2 equal halves. <em><u>Definition of an angle bisector.</u></em>

5. Equals substituted for equals leaves the condition unchanged. <em><u>You really don't have anything for this. </u></em> Each one of these blanks has it's own choices. You want something that talks about substituting an equal for another equal.

6. <em><u>None of your choices work here either. </u></em> Angle addition postulate is about the closest one. 2 equal parts added together equal the whole. The whole is twice as big as either one of the two equals. Together the 2 equals add up to the entire angle.

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Help plz :((<br> I'll give brainliest
Marina CMI [18]

Answer:

A. The source of energy for the water cycle is the sun.

B. Condensation would be the process that changes the water vapor into water droplets that form the cloud.

C. Arrow X would be runoff

3 0
3 years ago
Solve for X<br><br> PLEASE HELP ME
guapka [62]

Answer:

x = 10°

Step-by-step explanation:

Step 1:

92° + x° + 78° = 180°             Supplementary Angles

Step 2:

x° + 170° = 180°         Combine Like Terms

Step 3:

x° = 180° - 170°       Subtract 170° on both sides

Answer:

x = 10°

Hope This Helps :)

4 0
3 years ago
Help please I can’t figure it put
leonid [27]

5y + 3 >  -7 y + 13

Subtract 3 from both sides

5y > -7y + 13 - 3

Add 7y to both sides

5y + 7y > 13 - 3

12y > 10

Divide by 12, which is positive so the sign doesn't flip

y > 10/12 = 5/6

Answer: y > 5/6


8 0
3 years ago
4. Dominic is buying candy by the pound for a party. For every 10 pounds of
Debora [2.8K]

 

10 pounds of candy = $12

Cost, per pound, for the candy = 12 / 10 = <u>$1.2 </u>

 

 

5 0
3 years ago
The sum of the reciprocal of two consecutive odd integers is 44/483.Write a rational equation to solve the problem.
Arturiano [62]

Answer:

Step-by-step explanation:

Let consecutive odd integers be (2x + 1) and (2x + 3)

Their reciprocals are \frac{1}{2x + 1 }    and \frac{1}{2x + 3 }

\frac{1}{2x+1}+\frac{1}{2x+3}=\frac{44}{483}\\\\\frac{1*(2x+3)}{(2x+1)(2x+3)}+\frac{1*(2x+1)}{(2x+3)(2x+1)}=\frac{44}{483}\\\\\frac{2x + 3 + 2x +1}{(2x + 1)(2x+3)}=\frac{44}{483}\\\\\frac{4x + 4}{4x^{2}+8x+3}=\frac{44}{483}\\

483*(4x+4) = 44*(4x² + 8x + 3)

483*4x + 483*4 = 44*4x² + 44*8x  + 44*3

1932x + 1932 = 176x² + 352x + 132

176x² + 352x + 132 -1932x - 1932 = 0      

Combine like terms

176x² + 352x - 1932x - 1932 + 132 = 0

176x² - 1580x - 1800 = 0

Divide the equation by 4

44x² - 395x - 450 = 0

8 0
3 years ago
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