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Olenka [21]
3 years ago
10

The scale for a map is 20 miles =1/2 inch. The distance between two towns on the map is 3 and 3/4 inches. What is the actual dis

tance between these towns?
Mathematics
1 answer:
Fofino [41]3 years ago
4 0

Answer:

okbvghcfgcgfxdxdfffij,mhb

Step-by-step explanation:

You might be interested in
Helpp, since this question is a bit hard, ill give brainliest and 20 pts.
Morgarella [4.7K]

Step-by-step explanation:

A. When dealing with large numbers, sometimes it's easier to write them in a form of exponents of number ten. The value of the exponent shows how many times we multiply 10 by itself. That means that 10^3 is 10•10•10 or that 10^6 is 10•10•10•10•10•10.

So, when finding how many times on number is greater then the other, we need to divide them. We divide 8x10^6 by 2x10^5. It is done by dividing the numbers and subtracting the exponents; 8/2=4 and 10^6/10^5 is 10^6-5=10^1. So the correct answer is 4x10^1 which is 4x10, and that is 40.

B. Now, we have a total number of coins (2.25x10^5), and diametar of a coin (19mm = 19x10^-6km). Our task is to calculate the distance across which the coiks laid side-by-side would expand. We can find this by multiplying the number of coins with a diametar of single penny, 2.25x10^5•19x10^-6. Multiplying is done by multiplying the numbers (2.25x19=42.75) and adding the exponents (5+(-6)=5-6=-1). So, the distance is 42.75x10^-1km, which equals to 4.275 km. Obviously, this is less then the stated 5 km given in the text, so the reportet's statement is false.

5 0
3 years ago
2 Points
OlgaM077 [116]

Square and Rhombus are the following quadrilaterals have diagonals that are always  perpendicular to each other.

C. Square

D. Rhombus

<u>Step-by-step explanation:</u>

This implies the diagonals of a square and rhombus are perpendicular. The diagonals of a square and rhombus are a similar length. In elementary geometry, the property of being opposite is the connection between two lines which meet at a right angle. The property stretches out to other related geometric items.  

Principally Perpendicular lines will be lines that cross at a right (90 degrees) edge. so when it goes under shape rhombus and square have the equivalent of a considerable number of sides parallelly.

5 0
3 years ago
Read 2 more answers
Find a homogeneous linear differential equation with constant coefficients whose general solution is given by
frez [133]

Answer:

y" + 2y' + 2y = 0

Step-by-step explanation:

Given

y=c_1e^{-x}cosx+c_2e^{-x}sinx

Required

Determine a homogeneous linear differential equation

Rewrite the expression as:

y=c_1e^{\alpha x}cos(\beta x)+c_2e^{\alpha x}sin(\beta x)

Where

\alpha = -1 and \beta = 1

For a homogeneous linear differential equation, the repeated value m is given as:

m = \alpha \± \beta i

Substitute values for \alpha and \beta

m = -1 \± 1*i

m = -1 \± i

Add 1 to both sides

m +1= 1 -1 \± i

m +1= \± i

Square both sides

(m +1)^2= (\± i)^2

m^2 + m + m + 1 = i^2

m^2 + 2m + 1 = i^2

In complex numbers:

i^2 = -1

So, the expression becomes:

m^2 + 2m + 1 = -1

Add 1 to both sides

m^2 + 2m + 1 +1= -1+1

m^2 + 2m + 2= 0

This corresponds to the homogeneous linear differential equation

y" + 2y' + 2y = 0

6 0
3 years ago
The radius of a circular puddle is growing at a rate of 25 cm/sec.
tatiyna

Answer:

Step-by-step explanation:

a)area A=pi r^2

rate of change of area =dA/dt =2 pi r dr/dt

given dr/dt =25 ,r =50

rate of change of area =dA/dt =2 pi *50 *25 =2500pi=7854

area growing 7854 cm2/s

b)area A=pi r^2

rate of change of area =dA/dt =2 pi r dr/dt

given dr/dt =25 ,A =64

pi r^2 =64

=>r =8/√pi

rate of change of area =dA/dt =2 pi *(8/√pi) *25 =400√pi=708.98

area growing 708.98 cm2/s

8 0
3 years ago
Which expressions are equivalent to 4 to the 5 power choose all that apply
Nuetrik [128]

Answer:

since you didn't put the answer choices, this is what I know...

4 to the 5 power is 1024

it can be written as:

4x4x4x4x4 or 4^5

Step-by-step explanation:

7 0
2 years ago
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