
<u>the </u><u>given </u><u>expression</u><u> </u><u>can </u><u>be </u><u>solved </u><u>as </u><u>follows </u><u>~</u>

<u>taking </u><u>LCM </u><u>both </u><u>the </u><u>sides </u><u>,</u>

<u>on </u><u>cross </u><u>multiplying </u><u>,</u>

<u>let's</u><u> </u><u>now </u><u>gather </u><u>the </u><u>like </u><u>terms </u><u>at </u><u>either </u><u>sides </u><u>of </u><u>the </u><u>equation</u><u> </u><u>~</u>

<u>on </u><u>simplifying </u><u>the </u><u>equation</u><u> </u><u>,</u>

hope helpful ~
20th term= 119
Step-by-step explanation:
Let the first term of AP be a
and common difference be d
nth term is given by,
= a+(n-1)d
6th term = 35
a+(6-1)d= 35
a+5d=35 -----------------(i)
13th term = 77
a+12d= 77----------------(ii)
Now, equation (ii) - (i)
a+12d-(a+5d)= 77-35
a+12d-a-5d= 42
7d=42
d=6
Now, from equation (i)
a= 35-5d= 35-5(6)= 35-30 = 5
20th term= a+19d= 5+19(6)= 119
First you need to find the rate. This problem is based on the formula d = rt
d = distance
r = rate
t = time.
The question is asking how many miles will it travel in 8 hours so to find this out we need to find the rate when the car travels 240 miles in 4 hours. We use this information and plug it into the model d = rt
d = 240
r = don't know yet
t = 4 hr
d = rt
240 = 4r
240 / 4 = 4r / 4
60 = r
r = 60
So the car is going at a rate of 60 miles per hour. Now that we know this we can solve for how many miles the car will travel in 8 hours.
d = rt
d = r * t
d = 60 * 8
d = 480
So the car will travel 480 miles in 8 hours
Another way to think about this is that you know the car traveled 240 miles in 4 hours and the question is wanting to know how far the car will travel in 8 hours, which would be double the 4 hours so 240 + 240 = 480