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larisa86 [58]
3 years ago
7

the area of a rectangle is 85 square feet. the length is 12 feet longer than the width. find the length and width of the wall

Mathematics
1 answer:
Fed [463]3 years ago
3 0
Formula for area of rectangle:
A=L x w
Here A=85 square ft
Length, L=w+12

Put values in formula.
85=(w+12)w
85=w^2+12w
Subtract 85 from both sides
w^2+12w-85=0
Factorise the equation.
(w-5)(w+17)=0
w=5 and w=-17
Ignore the negative value of width.
Width, w= 5 ft  and Length, L=12+5=17 ft

Answer: Width=5 ft and Length=17 ft
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<h3>How to determine the equivalent expression?</h3>

The expression is given as:

\frac{14x^4y^6}{7x^8y^2}

Divide 14 by 7

\frac{14x^4y^6}{7x^8y^2} = \frac{2x^4y^6}{x^8y^2}

Apply the law of indices

\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{6-2}}{x^{8-4}}

Evaluate the differences in the exponents

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3 years ago
Please help Factor completely. Show your work (as much work as possible, including a ​list of factors if
defon

Answer:

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x = -5

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