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KATRIN_1 [288]
3 years ago
12

I REALLY need help with these 3 questions plz!!!!

Mathematics
1 answer:
Tanzania [10]3 years ago
7 0

Answer:

6. No. See explanation below.

7. 18 months

8. 16

Step-by-step explanation:

6. To rewrite a sum of two numbers using the distributive property, the two numbers must have a common factor greater than 1.

Let's find the GCF of 85 and 99:

85 = 5 * 17

99 = 3^2 + 11

5, 3, 11, and 17 are prime numbers. 85 and 99 have no prime factors in common. The GCF of 85 and 99 is 1, so the distributive property cannot be used on the sum 85 + 99.

Answer: No because the GCF of 85 and 99 is 1.

7.

We can solve this problem with the lest common multiple. We need to find a number of a month that is a multiple of both 6 and 9.

6 = 2 * 3

9 = 3^2

LCM = 2 * 3^2 = 2 * 9 = 18

Answer: 18 months

We can also answer this problem with a chart. We write the month number and whether they are home or on a trip. Then we look for the first month in which both are on a trip.

Month                Charlie          Dasha

1                          home             home

2                          home             home

3                          home             home

4                          home             home

5                          home             home

6                         trip                home

7                          home             home

8                          home             home

9                          home             trip

10                         home             home

11                         home             home

12                         trip               home

13                         home             home

14                         home             home

15                         home             home

16                         home             home

17                         home             home

18                         trip                 trip

Answer: 18 months

8.

First, we find the prime factorizations of 96 an 80.

96 = 2^5 * 3

80 = 2^4 *5

GCF = 2^4 = 16

Answer: 16

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63,889 rounded to the nearest hundred is 63,900
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3 years ago
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aniked [119]

Answer:

:)

Step-by-step explanation:

Examples: 1+2, 1/3+1/4, 2^3 * 2^2

(x+1)(x+2) (Simplify Example), 2x^2+2y a x=5, y=3 (Evaluate Example)

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JKLM is a rhombus. KM is 6 and JL is 8. Find the perimeter of the rhombus. image of rhombus JKLM with diagonals JL and KM inters
VLD [36.1K]
If a quadrilateral is a rhombus then:

i) all its sides have equal length,

and

ii) the 2 diagonals are perpendicular and bisect each other.


The 2 diagonals of rhombus JKLM intersect at N.

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thus, by the Pythagorean theorem, 

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4 0
3 years ago
Can someone please help me
Evgesh-ka [11]

Answer:

UW ≈ 6.55 ≈ 7

Step-by-step explanation:

cos (35) = adjacent/hypotenuse

cos(35) = UW/VW

cos(35) = UW/8

8*cos(35) = UW

UW ≈ 6.55

Hope this helped! <3

7 0
3 years ago
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