All categories

2 years ago

Solve the equation below

Mathematics

2 answers:

Elina [12.6K]2 years ago

7 0

Answer:

(-5,3)

Step-by-step explanation:

-40+8y=-16

8y=24

y=3

Anastasy [175]2 years ago

6 0

Answer:

(-5, -7)

Step-by-step explanation:

insert -5 where you see the variable 'x':

-8(-5) + 8y = -16

40 + 8y = -16

8y = -56

y = -7

You might be interested in

Mark was thinking of a number. Mark doubles it, then adds 11 to get an answer of 52.6. What was the original number?

Artemon [7]

Answer:

20.8

Step-by-step explanation:

The first step you need to do is to subtract 11:

52.6 - 11 = 41.6

The second step is to divide it by 2:

41.6 / 2 = 20.8

Mark was thinking of 20.8

5 0

2 years ago

Read 2 more answers

What is the simplified expression for the perimeter of the polygon?

Tanzania [10]

Not sure but i think b

5 0

2 years ago

Dora spent $45 and has $32 left. Which equation can be used to calculate how much money Dora had at the beginning?

r-ruslan [8.4K]

32+45 can be used to figure out the starting amount

7 0

3 years ago

Read 2 more answers

A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores

EastWind [94]

Answer:

$(52-49) -4.300= -1.300$

$(52-49) +4.300= 7.300$

And the 95% confidence would be :

$-1.300 \leq \mu_1 -\mu_2 \leq 7.300$

Step-by-step explanation:

We have the following info given from the problem

$\bar X_1 = 52$ sample mean for this year

$s_1= 13$ sample deviation for this year

$n_1 = 75$ random sample selected for this year

$\bar X_2 = 49$ sample mean for last year

$s_2= 11$ sample deviation for last year

$n_1 = 53$ random sample selected for last year

And we want to construct a 95% confidence interval estimate of the difference μ1−μ2, where μ1 is the mean of this year's sales and μ2 is the mean of last year's sales

For this case the formula that we need to use is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

The degrees of freedom are given by:

$df= n_1 +n_2 -2 = 75+53-2= 126$

The confidence level is 0.95 and the significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ so then the critical value for this case is :

$t_{\alpha/2}= 1.979$

The margin of error would be:

$ME = 1.979 \sqrt{\frac{13^2}{75} +\frac{11^2}{49}}= 4.300$

And the confidence interval would be given by:

$(52-49) -4.300= -1.300$

$(52-49) +4.300= 7.300$

And the 95% confidence would be :

$-1.300 \leq \mu_1 -\mu_2 \leq 7.300$

6 0

3 years ago

PLS SOMEONE HELP BEEN STUCK ON QUESTION FOR 20 MIN I DONT UNDERSTAND

o-na [289]

What the equation is looking for is the values X needs to have to equal zero

X - 6 = 0
X - 6 (+6)= 0 (+6)
X = 6

X + 2 = 0
X + 2 (-2)= 0(-2)
X = -2

i don't understand what the question is asking for the topmost box though

8 0

3 years ago