times more stars are there in universe compared to human eye can see
<h3><u>
Solution:</u></h3>
Given that, conservative estimate of the number of stars in the universe is 
The average human can see about 3,000 stars at night with only their eyes
To find: Number of times more stars are there in the universe, compared to the stars a human can see
Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see
Then from given statement,
<em><u>Substituting given values we get,</u></em>
Thus times more stars are there in universe compared to human eye can see
Answer:
the answer is 26
Step-by-step explanation:
you add 7 to -7 and 19. the positive and negative 7 cancels each other out. them you add 19 and 7 which is 26. that means x is 26.
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Answer:
112in²
Step-by-step explanation:
Formulas: V = 
, V = lwh
Sub: v = 
Solve: 32
Sub: v = 4 x 4 x 5
Solve: 80
V = 80 + 32
V = 112
<u>The total volume of the figure is 112in²</u>
Using geometric sequence concepts, it is found that:
a) The rule is: 
.
b) An exponential relationship exists between the two variables.
<h3>What is a geometric sequence?</h3>
A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.
The nth term of a geometric sequence is given by:
In which 
is the first term.
A geometric sequence represents an exponential relationship between the variables.
In this problem, considering that the first-place finisher wins half of $1.500.000 in total prize money, and each finisher earns half of the one who finished above, the first term and the common ratio are given by:
.
Hence the nth term of the sequence is given by:
More can be learned about geometric sequence concepts at brainly.com/question/11847927
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Answer:
69
Step-by-step explanation:
because it is like has beyer
