Step-by-step explanation:
When we factorise the denominator into prime factors and there are only numbers 2 and 5, the decimal is finite.
Otherwise the decimal is infinite repeating.
Examples:

We have

Answer:
Solving the expression
we get 6
The answer is 6.
Step-by-step explanation:
We need to find value of expression: ![\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-%5Cfrac%7B18%7D%7B%5Csqrt%7B81%7D%20%7D%20-2%29)
We know that 
Our expression will become
![\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{\sqrt{81} } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-\frac{18}{9 } -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-2 -2)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}-(-4)\\=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-%5Cfrac%7B18%7D%7B%5Csqrt%7B81%7D%20%7D%20-2%29%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-%5Cfrac%7B18%7D%7B9%20%7D%20-2%29%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-2%20-2%29%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D-%28-4%29%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D%2B4)
We can write ![\sqrt[6]{8}=(2^3)^{\frac{1}{6}}=(2)^{\frac{3}{6}}=2^\frac{1}{2}=\sqrt{2} \\](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B8%7D%3D%282%5E3%29%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%3D%282%29%5E%7B%5Cfrac%7B3%7D%7B6%7D%7D%3D2%5E%5Cfrac%7B1%7D%7B2%7D%3D%5Csqrt%7B2%7D%20%20%5C%5C)
Now, replacing ![\sqrt[6]{8}=\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B8%7D%3D%5Csqrt%7B2%7D)
![=\frac{2}{\sqrt[6]{8} }.\sqrt{2}+4\\=\frac{2}{\sqrt{2} }.\sqrt{2}+4\\=2+4\\=6](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B6%5D%7B8%7D%20%7D.%5Csqrt%7B2%7D%2B4%5C%5C%3D%5Cfrac%7B2%7D%7B%5Csqrt%7B2%7D%20%7D.%5Csqrt%7B2%7D%2B4%5C%5C%3D2%2B4%5C%5C%3D6)
So, solving the expression
we get 6
Answer:
2
Step-by-step explanation:
Simplify the following:
(-6 - 4)/(-5)
Hint: | Group the negative terms in -6 - 4 together and factor out the minus sign.
-6 - 4 = -(6 + 4):
(-(6 + 4))/(-5)
Hint: | Evaluate 6 + 4.
6 + 4 = 10:
(-10)/(-5)
Hint: | In (-10)/(-5), the numbers 10 in the numerator and -5 in the denominator have gcd greater than one.
The gcd of 10 and -5 is 5, so (-10)/(-5) = (-(5×2))/(5 (-1)) = 5/5×(-2)/(-1) = (-2)/(-1):
(-2)/(-1)
Hint: | Cancel common terms in the numerator and denominator of (-2)/(-1).
(-2)/(-1) = (-1)/(-1)×2 = 2:
Answer: 2
Make them count jelly beans.
The lcm of 6 and 18 is C.)18