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3 years ago

What is: −6 − (−4)? i need to know

Mathematics

2 answers:

olga_2 [115]3 years ago

6 0

Answer:

-2

Step-by-step explanation:

Make it simpler: -6 + 4
-6 + 4 = -2

Why:

When you subtract a negative, it automatically becomes a positive. That's why when we were making it simpler above, we canceled out the two minus signs (subtractions sign and negative sign) to make a positive 4. That's why we added a positive instead of subtracting a negative.
A negative plus a positive will get bigger. That's why -6 + 4 = -2. The -2 is larger than -6 when you look at it on a number line. It's closer to 0 and the positives.

nignag [31]3 years ago

5 0

Answer:

-2

Step-by-step explanation:

-6-(-4)

-6+4

-2

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konstantin123 [22]

Answer:

$13.10 represents the rate of change

Step-by-step explanation:

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2 years ago

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

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First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

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$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

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So, the function is defined for x≥1.

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3 years ago

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tankabanditka [31]

Step-by-step explanation:

2(3(7)-1)

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3 years ago

What are the two solutions of 2x^2 = -X^2 - 5x - 1?

Sidana [21]

Answer:

Step-by-step explanation:

Let's solve 2x^2 = -X^2 - 5x - 1. Consolidate all terms on the left side and write 0 on the right side:

3x^2 + 5x + 1 = 0. This is a quadratic equation. Let's solve it for x using the quadratic formula:

a = 3, b = 5, c = 1, and so the discriminant is b^2 - 4ac = 5^2 - 4(3)(1) = 13. Because the discriminant is positive, we know that there are two distinct, real roots; the graphs of y = 2x^2 and y = x^2 - 5x - 1 intersect in two places whose x-coordinates are the real roots mentioned above.

Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."

Answer C would be correct if and only if we write y = x^2 - 5x - 1.

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3 years ago

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3 years ago

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