Answer:
280 students
111 non students
Step-by-step explanation:
number of students (S)
number of non students (N)
S+N=391 S=391-N
4S+6N=1786
substitute S
4(391-N)+6N=1786
1564-4N+6N=1786
subtract 1564 from each side
2N=222
N=111
S=391-111=280
Answer:
The value in millions of dollars of a downtown office building that cost 12 million dollars to build 20 years ago and depreciated at 9% per year is $1819738.95
Step-by-step explanation:
Cost of building 20 years ago = 12000000
We are given that the cost depreciated at 9% per year
Formula : 
Where N(t)= Population after t years
=Initial population=12000000
r= rate of depreciation=0.09
t = 20 years
Substitute the values in the formula:

N(t)=1819738.95
Hence the value in millions of dollars of a downtown office building that cost 12 million dollars to build 20 years ago and depreciated at 9% per year is $1819738.95
Answer:
b = 6 units
Step-by-step explanation:
Area = 1/2bh
8 = 1/2(b)(8/3)
divide both sides by 1/2
16 = b(8/3)
multiply both sides by 3
48 = 8b
divide both sides by 8
b = 6 units
For your boxes:
1/2 x b/1 x 8/3 = 8/1
b/1 x 8/3 = 16/1
8b/3 / 8 = 2/1
b/3 x 3 = 6
Answer: the answer is c
Step-by-step explanation: the first line is the min and the next is q1 and then the medium and q3 max
We will use a Future Value Formula:
FV=PV(1 + i)ⁿ
$939 is our Present Value (PV)
.06 (6%) will be substitued for i (interest)
6 years will be substituated for "n" (numbers of periods)
FV = $939 (1 + .06) ^6
FV = 1331.989446 or rounded to <u>1331.99 balance at the end of 6 years</u>