3 years ago

State the domain and range of the function represented by the table.

Mathematics

1 answer:

Grace [21]3 years ago

3 0

SORRY IF I'M WRONG ...

Answer: Domain:{-4,-1,0,3) Range:{-4}

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The functions f and g are defined by f: x = 4 - x and g: x = hx² + k. If the composite function gf is given by gf: x + 2x² - 16x

kozerog [31]

Answer:

Step-by-step explanation:

f(x) = 4-x

g(x) = h $x^{2}$ +k

g(f(x)) = 2 $x^{2}$ -16x+26

so put f(x) in g(x)

h $(4-x)^{2}$ +k

h((4-x)(4-x) + k

h( $x^{2}$ -8x+16)+k

if h = 2 , then

2 $x^{2}$ -16x+32 + k

and we want 26 instead of 32 so subtract 6 so K = (-6)

2 $x^{2}$ -16x+32 + (-6)

2 $x^{2}$ -16x+32 - 6

2 $x^{2}$ -16x+26

h=2

k=(-6)

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2 years ago

Select all equations for which -3 is a solution.

ad-work [718]

Answer:

look it up

Step-by-step explanation:

7 0

3 years ago

Simplify (15x2 – 24x + 9) ÷ (3x – 3) = ?

larisa86 [58]

$\frac{15x^{2} - 24x + 9}{3x - 3} = \frac{3(5x^{2}) - 3(8x) + 3(3)}{3(x) - 3(1)} = \frac{3(5x^{2} - 8x + 3)}{3(x - 1)} = \frac{5x^{2} - 5x - 3x + 3}{x - 1} = \frac{5x(x) - 5x(1) - 3(x) - 3(-3)}{x - 1} = \frac{5x(x - 1) - 3(x - 1)}{x - 1} = \frac{(5x - 3)(x - 1)}{x - 1} = 5x - 3$