Ask question

Ask question

All categories

3 years ago

6

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

t to x from the second equation is substituted into the first equation.
3x + 2y = −21
x − 3y = 4

1 answer:

larisa [96]3 years ago

4 0

What are your answer choices? I’m not sure which equation they are asking for?

The solution to this system of equations is
X= -5
Y= -3

You might be interested in

Please answer question three and four if you can :)<br> Show full working out ty;)

nikklg [1K]

Step-by-step explanation:

3

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

$D = ( \frac{2 + 5}{2}, \: \: \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \: \: \frac{ 1}{2} ) \\ \therefore D= (3.5, \: \: 0.5) \\ \& \: A=(-1,\:\:4)...(given) \\\\ now \: by \: distance \: formula \\ \\ Length \: of \: segment \: AD \\ = \sqrt{( - 1 - 3.5)^{2} + {(4 - 0.5)}^{2} } \\ = \sqrt{(4.5)^{2} + {(3.5)}^{2} } \\ = \sqrt{20.25 + 12.25 } \\ = \sqrt{32.5} \\ \red{ \boxed{\therefore Length \: of \: segment \: AD = 5.7 \: units}}$

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

$\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\$

is the equation of line AB.

Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

$LHS = 3x - y-5\\=3\times 4-7-5\\= 12-12\\=0\\= RHS$

Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

4 0

3 years ago

I need an answer what is 1.03 ÷ (-10.3)=?

Sloan [31]

The answer is $- \frac{1}{10}$
To figure this out, convert both numbers to fractions. 1.03 = 1 $\frac{3}{100}$ and (-10.3) = -10 $\frac{3}{10}$ . Now, convert to improper fractions.
1 $\frac{3}{100} = [tex] \frac{103}{100}$
-10 $\frac{3}{10}$ = $- \frac{103}{10}$
Now, divide. Dividing fractions is the same as multiplying by the reciporical. So:
$-\frac{103}{10} \ becomes\ \frac{10}{103}$
$\frac{103}{100} *- \frac{10}{103} = -\frac{1030}{10300} = - \frac{1}{10}$

5 0

3 years ago

dentify all of the following solutions of square root of x minus 8 end root plus 8 equals x. (1 point)

viva [34]

Answer:gh

Step-by-step explanation:

3 0

3 years ago

How are dilations and functions related?

Anika [276]

If we dialate a function we are just changing what the graph looks like by a stretch or a compression, the function really doesn't change. If a function before the dilation, then it is a function after the dilation. The opposite is also true.

5 0

2 years ago

Read 2 more answers

Quadrilateral ABCD has vertices at A(0,0), B(0,2), C(6,2), and D(6,0). Find the vertices of the quadrilateral after a dilation w

valentinak56 [21]

Answer:

A=0

B=0,3

C=9,3

D=9,0

Step-by-step explanation:

Multiplies all the vertices bay scale factor 3/2

5 0

2 years ago