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Marianna [84]
3 years ago
7

I will mark brainliest to whoever gets this answer! Please help!

Mathematics
2 answers:
ra1l [238]3 years ago
5 0

Answer: 20 yards.

Step-by-step explanation:

To find the area of the shaded region (in blue), first find the area of the right triangle and the rectangle.

Rectangle.

Use a = lw (area = length x width) since you are already given the values

a = lw = 3*4=12

Right triangle.

Use a= \frac{1}{2} ab to find the area of a right triangle, in which a and b are legs (not the hypotenuse.

a = \frac{1}{2} ab = \frac{1}{2} *8*8 = 32

Subtract the area of the rectangle from the right triangle to find the area of the shaded region.

32-12=20

The answer is 20 yards.

lisov135 [29]3 years ago
4 0

Answer:

20 yd²

Step-by-step explanation:

This problem is really easy once you break it down!

First, find the area of the triangle.

A = \frac{1}{2}bh

b = 5 + 3 = 8

h = 4 + 4 = 8

A = \frac{1}{2}*8*8

A = 32

Now find the area of the square.

A = lw

A = 4*3

A = 12

The last step is to subtract.

Area of triangle - area of rectangle =

32 - 12 = 20

20 yd²

Hope this helped! :)

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Thanks in advance for your help, the question is;
valkas [14]

Answer:

8, 9

Step-by-step explanation:

1/2x + 2(x + 1) = 22

1/2x + 2x + 2 = 22

1/2x + 2x = 20

5/2x = 20

5x = 40

x = 8

8, 9

4 + 18 = 22

5 0
3 years ago
Read 2 more answers
F(x)=3x+2 and g(x)=-2x-4, find h(x)= f(x)-g(x)
Katena32 [7]


substitute for your equation;

h(x) = f(x) - g(x)

h(x) = (3x + 2) - (-2x -4)

h(x) = 3x + 2 + 2x + 4 (minus and minus = addition)

h(x) = 3x + 2x + 2 + 4 (combine like terms)

h(x) = 5x + 6

Hope that helps! :D

8 0
3 years ago
I need to know the improper fractions answers for:
zmey [24]

Answer:

Part 1) x=\frac{15}{2}\ units

Part 2) z=\frac{15\sqrt{3}}{2}\ units

Part 3) y= \frac{15\sqrt{3}}{4}\ units

Part 4) b= \frac{45}{4}\ units

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

cos(60^o)=\frac{x}{15} ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

cos(60^o)=\frac{1}{2}

substitute

\frac{1}{2}=\frac{x}{15}

solve for x

x=\frac{15}{2}\ units ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

15^2=x^2+z^2

substitute the value of x

15^2=(\frac{15}{2})^2+z^2

solve for z

z^2=15^2-(\frac{15}{2})^2

z^2=225-\frac{225}{4}

z^2=\frac{675}{4}

z=\frac{\sqrt{675}}{2}\ units

simplify

z=\frac{15\sqrt{3}}{2}\ units

step 3

Find the value of y

In the right triangle of the right

sin(30^o)=\frac{y}{z} ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

sin(30^o)=\frac{1}{2}

so

\frac{1}{2}=y:\frac{15\sqrt{3}}{2}

solve for y

\frac{1}{2}= \frac{2y}{15\sqrt{3}}

y= \frac{15\sqrt{3}}{4}\ units

step 4

Find the value of b

In the right triangle of the right

cos(30^o)=\frac{b}{z} ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

cos(30^o)=\frac{\sqrt{3}}{2}

so

\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}

solve for y

\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}

b= \frac{45}{4}\ units

7 0
3 years ago
The sum of a twice a number and three is 15. What is the number?
SOVA2 [1]

Answer:

The answer is 6. Does that help?

6 0
3 years ago
Simplify and state the excluded values for <br> P+4/p^2+6p+8
AlladinOne [14]
We have that
p+4/p²<span>+6p+8

we know that
</span><span>the denominator can not be zero
so
the domain of the function is all real numbers except zero

</span>p+4/p²+6p+8--------> multiply by p² all expression
<span>p</span>²*(p)+p²*(4/p²)+p²*(6p)+p²*8
<span>p</span>³+4+6p³+8p²
<span>7p</span>³+8p²+4<span>
</span><span>
</span>
3 0
3 years ago
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