Can someone personally help me with geometry and area? Please I have more questions like that
2 answers:
Answer:
272
Step-by-step explanation:
<h3>Finding the area on this problem has only a couple steps. First I divided the picture into two parts a rectangle and a triangle. I first found the area of the rectangle. The formula to finding a rectangle is base times height. In this case the base has a length of 19 in and has a height of 8 in. So the area of the rectangle would be 19*8= 152. Now we find the area of the triangle. To find the area of a triangle you use the formula base*height*1/2. In this case you do 20 * 12 * 1/2 = 120. Now for the last step add the areas together in this case 152+120=272. If you need help with finding the lengths reach out to me.</h3><h3>p.s. I’m not actually 61</h3>
Answer:
The area of the shaded region is 272 in²
Step-by-step explanation:
Since it is an odd shape, the real height(20 inches according to the picture) will help us alot. But first you'll want to split the shapes. and find the areas seperately in a way. I see a rectangle on the top and triangle on the bottom. Lets find the area of the rectangle first.
To find the area, you have to multiply length and width.
A = L x W
19 x 8 = 152(the area)
So now we know the area of the rectangle, but what about the triangle? Since there is no exact base measurement for the triangle, we will add the length of the rectangle(19) and the 1 inch.
19 + 1 = 20
So the base for the triangle is 20.
To find the height of the triangle, subtract 8(the rectangle's width) from the overall height(20 inches).
20 - 8 = 12
A = b ÷ 2
A= 120(area)
That is not the overall area yet, we have to add the two areas now.
152 + 120 = 272
That is how you find the area for this, let me know if you need anymore help.
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This question has this set of answer choices:
a) when the plane cuts three faces of the cube, separating one corner from the others
b) when the plane passes through a pair of vertices that do not share a common face
c) when the plane is perpendicular to the base and intersects two adjacent vertical faces
d) when the plane makes an acute angle to the base and intersects three vertical faces
e) not enough information to answer the question
The right answer is the first choice: a) when the plane cuts three faces of the cube, separating one corner from the others
You can see a picture of this case in the figure attached: as you can see the cross section (in pink) is a triangle.
a) when the plane cuts three faces of the cube, separating one corner from the others
b) when the plane passes through a pair of vertices that do not share a common face
c) when the plane is perpendicular to the base and intersects two adjacent vertical faces
d) when the plane makes an acute angle to the base and intersects three vertical faces
e) not enough information to answer the question
The right answer is the first choice: a) when the plane cuts three faces of the cube, separating one corner from the others
You can see a picture of this case in the figure attached: as you can see the cross section (in pink) is a triangle.