F(1) = -2 and g(4) = 6
-8 • -2 - 4 • 6
16 - 24 = -8
Answer:
he answer is (2), (4) and (6).
Step-by-step explanation:
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Answer:
1+cos^2(2A)=(1−cos2(2A))+2cos^2(2A)
=sin^2(2A)+2(cos^2A−sin^2A)^2
=(2sinAcosA)^2+2(cos^4A−2cos^2Asin^2A+sin^4A)
=2(cos^4A+sin^4A)
Step-by-step explanation:
Answer:
Depreciation should be on a value net of VAT.
Cost + (Cost * VAT) = 402,500
Cost + Cost * 15% = 402,500
1.15 * Cost = 402,500
Cost = $350,000
Depreciation is straight line for 6 years so per year is = 350,000/6 = $58,333
2019
In 2019 the June year end from date of purchase will be 10 months.
Depreciation in 2019
= Yearly depreciation * 10/12 months
= 58,333 * 10/12
= $48,611
Accumulated Depreciation 2019
= $48,611
2020
2020 will be a complete year so depreciation
= $58,333
Accumulated Depreciation 2020
= 2019 + 2020
= 48,611 + 58,333
= $106,944