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2 years ago

What is the area of a circle if the circumference is 29

Mathematics

1 answer:

Kruka [31]2 years ago

8 0

Answer:

67 square units

Step-by-step explanation:

Circumference/pi = diameter

29/3.14 = 9.24

Radius = 9.24/2 = 4.62

A = pi * r^2

A = 3.14 * 4.62^2 = 67 square units

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Layla reads 2/5 of her book on Saturday and the other 90 pages to finish the book on Sunday how many pages does Layla's book hav

PolarNik [594]

3/5=90
1/5=30
30x5=150
laylas book has 150 pages

5 0

3 years ago

I need help on this one and the one at the bottom

KiRa [710]

The last awnser is 15x + 2 and the first one is explained below:
65 X 1.5 = 97.5
97.5 + 95 = 192.5
192.5 is awnser
If you want me to explain in more detail comment on my user i will check my notifications and help you out !!! :D
PEACE YALL

3 0

3 years ago

Write an equation for a quadratic function that has x intercepts (-3, 0) and (5, 0)

Blizzard [7]

Answer:

One possible equation is $f(x) = (x + 3)\, (x - 5)$ , which is equivalent to $f(x) = x^{2} - 2\, x - 15$ .

Step-by-step explanation:

The factor theorem states that if $x = x_{0}$ (where $x_{0}$ is a constant) is a root of a function, $(x - x_{0})$ would be a factor of that function.

The question states that $(-3,\, 0)$ and $(5,\, 0)$ are $x$ -intercepts of this function. In other words, $x = -3$ and $x = 5$ would both set the value of this quadratic function to $0$ . Thus, $x = -3\!$ and $x = 5\!$ would be two roots of this function.

By the factor theorem, $(x - (-3))$ and $(x - 5)$ would be two factors of this function.

Because the function in this question is quadratic, $(x - (-3))$ and $(x - 5)$ would be the only two factors of this function. In other words, for some constant $a$ ( $a \ne 0$ ):

$f(x) = a\, (x - (-3))\, (x - 5)$ .

Simplify to obtain:

$f(x) = a\, (x + 3)\, (x - 5)$ .

Expand this expression to obtain:

$f(x) = a\, (x^{2} - 2\, x - 15)$ .

(Quadratic functions are polynomials of degree two. If this function has any factor other than $(x - (-3))$ and $(x - 5)$ , expanding the expression would give a polynomial of degree at least three- not quadratic.)

Every non-zero value of $a$ corresponds to a distinct quadratic function with $x$ -intercepts $(-3,\, 0)$ and $(5,\, 0)$ . For example, with $a = 1$ :