Evaluate 3 1/3 + - 7/4
1 answer:
You might be interested in
Answer:
The probability that the cell will be killed is 0.9328.
Step-by-step explanation:
We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.
Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be ''.
This means that the cell will get killed if happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.
Here, P() = 0.2, P(
) = 0.4, P(
) = 0.3, P(
) = 0.6, P(
) = 0.5.
So, the probability that the cell will be killed is given by;
P(A)=
P(A) =
P(A) =
P(A) = 1 - 0.0672 = 0.9328
Hence, the probability that the cell will be killed is 0.9328.