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Yanka [14]
3 years ago
15

35. Explain the difference between the reciprocal of x^2

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

As you can see, the difference between the reciprocal of x^2 and the inverse of   x^2 is that \frac{1}{x^2} =x^{-2} and \sqrt{x} =x^{\frac{1}{2}.

Step-by-step explanation:

First lets find both the reciprocal of x^2 and the inverse of

Recall that the reciprocal of a value is where you take a fraction and swap the places of the terms. In the case of x^2, 1 is the denominator, so

\frac{x^2}{1} =\frac{1}{x^2}

To find the inverse of a function, you first need swap the locations of x and y in the equation

y=x^2\\\\x=y^2

Now, you need to solve for y

y^2=x\\\\y=\sqrt{x}

Now, lets rewrite each of these to better compare them

\frac{1}{x^2} =x^{-2}\\\\\sqrt{x} =x^{\frac{1}{2}

As you can see, the difference between the reciprocal of x^2 and the inverse of

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