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EastWind [94]
3 years ago
11

What does 7/8-6/7 equle

Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0

Answer:

1/56

Step-by-step explanation:

7

8

−

6

7

=

1

56

(Decimal: 0.017857)

Marysya12 [62]3 years ago
3 0

Answer: 0.01785714285 is what it is in decimal form AND

1/56 in fraction form.

Step-by-step explanation:

So we are given 7/8 - 6/7.

WE have to find what it is:

0.01785714285 is what it is in decimal form AND

1/56

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For the equation y = - 3x + 2 2. determine the value of y when x = 2?
sergejj [24]
Y = -3(2) +22
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8 0
3 years ago
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Identify whether the series sigma notation infinity i=1 15(4)^i-1 is a convergent or divergent geometric series and find the sum
const2013 [10]

Answer:  The correct option is

(d) This is a divergent geometric series. The sum cannot be found.

Step-by-step explanation: The given infinite geometric series is

S=\sum_{i=1}^{\infty}15(4)^{i-1}.

We are to identify whether the given geometric series is convergent or divergent. If convergent, we are to find the sum of the series.

We have the D' Alembert's ratio test, states as follows:

Let, \sum_{i=1}^{\infty}a_i is an infinite series, with complex coefficients a_i and we consider the following limit:

L=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}.

Then, the series will be convergent if  L < 1 and divergent if  L > 1.

For the given series, we have

a_i=15(4)^{i-1},\\\\a_{i+1}=15(4)^i.

So, the limit is given by

L\\\\\\=\lim_{i\rightarrow \infty}\dfrac{a_{i+1}}{a_i}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i-1}}\\\\\\=\lim_{i\rightarrow \infty}\dfrac{15(4)^i}{15(4)^{i}4^{-1}}\\\\\\=\dfrac{1}{4^{-1}}\\\\=4>1.

Therefore, L >1, and so the given series is divergent and hence we cannot find the sum.

Thuds, (d) is the correct option.

7 0
4 years ago
Read 2 more answers
Ellus
butalik [34]

9514 1404 393

Answer:

  2.25

Step-by-step explanation:

Add the square of half the x-coefficient to complete the square.

  (-3/2)² = 9/4 = 2.25

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