All categories

3 years ago

Please I need help with this math homework ASAP thank you!

Mathematics

1 answer:

Montano1993 [528]3 years ago

4 0

Answer:

$\sqrt{4} = 2 \\ \\ \sqrt{2} \times \sqrt{8 } = \sqrt{16} \\ \\ \sqrt{16} = 4$

You might be interested in

So I have been working on this question, and I am confused on how to solve it. I looked in my text, but I do not understand. I w

Anit [1.1K]

M∠LMN + m∠NMO = m∠LMO

This is true because these two angles together form the larger angle. This means that the measure of each piece will add together to form the whole thing.

7 0

3 years ago

Read 2 more answers

A damsel in distress is being

umka2103 [35]

Check the picture below.

make sure your calculator is in Degree mode.

6 0

3 years ago

PLEASE HELP!!!!!!!!!!!!!!!!

maksim [4K]

Answer:

Step-by-step explanation:

x+2/x = 3/2

(x + 2)*2 = 3*x {cross multiplication}

2x + 4 =3x

2x-3x = -4

-x = -4

x = 4

5 0

3 years ago

Researchers randomly divided 500 volunteers into two equal-sized groups. One group spent 6 months on the Paleo diet. A control g

gtnhenbr [62]

Answer:

$p_v =P(t_{(498)}>1.356)=0.088$

And we can use the following excel code to find it: "=1-T.DIST(1.356,498,TRUE)"

Step-by-step explanation:

Data given and notation

$\bar X_{P}=7$ represent the mean for the sample Paleo

$\bar X_{C}=5$ represent the mean for the sample Control

$s_{P}=20$ represent the sample standard deviation for the sample Paleo

$s_{C}=12$ represent the sample standard deviation for the sample Control

$n_{P}=250$ sample size selected Paleo

$n_{C}=250$ sample size selected Control

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the Paleo diet provides more weight control than the control treatment, the system of hypothesis would be:

Null hypothesis: $\mu_{P}-\mu_{C}\leq 0$

Alternative hypothesis: $\mu_{P}-\mu_{C}>0$

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{P}-\bar X_{C})-12}{\sqrt{\frac{s^2_{P}}{n_{P}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(7-5)-0}{\sqrt{\frac{20^2}{250}+\frac{12^2}{250}}}}=1.356$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{P}+n_{C}-2=250+250-2=498$

Since is a one side right test the p value would be:

$p_v =P(t_{(498)}>1.356)=0.088$

And we can use the following excel code to find it: "=1-T.DIST(1.356,498,TRUE)"

8 0

3 years ago

Click on the value for p that makes this<br> inequality true.<br> P2 -12

Nataliya [291]

Answer:

Step-by-step explanation:

5 0

4 years ago